opposite sides, is equal to three-fourths of the sum of the squares on the sides of the triangle. 45. If any number of parallelograms be constructed having their sides of given length, shew that the sum of the squares on the diagonals of each will be the same. 46. ABCD is a right-angled parallelogram, and AB is double of BC; on AB an equilateral triangle is constructed: shew that its area will be less than that of the parallelogram. 47. A point is taken within a triangle ABC, such that the angles BOC, COA, AOB are equal; prove that the squares oa BC, CA, AB are together equal to the rectangles contained by OB, OC; OC, OA; OA, OB; and twice the sum of the squares on OA, OB, OC. BOOK III. POSTULATE. A POINT is within, or without, a circle, according as its distance from the centre is less, or greater than, the radius of the circle. DEF. I. A straight line, as PQ, drawn so as to cut a circle ABCD, is called a SECANT. That such a line can only meet the circumference in two points may be shewn thus: Some point within the circle is the centre; let this be 0. Join OA. Then (Ex. 1, 1. 16) we can draw one, and only one, straight line from O, to meet the straight line PQ, such that it shall be equal to OA. Let this line be OC. Then A and C are the only points in PQ, which are on the circumference of the circle. S. E. II. DEF. II. The portion AC of the secant PQ, intercepted by the circle, is called a CHORD. DEF. III. The two portions, into which a chord divides the circumference, as ABC and ADC, are called ARCS. B P D DEF. IV. The two figures into which a chord divides the circle, as ABC and ADC, that is, the figures, of which the boundaries are respectively the arc ABC and the chord AC, and the arc ADC and the chord AC, are called SEGMENTS of the circle. DEF. V. The figure AOCD, whose boundaries are two radii and the arc intercepted by them, is called a SECTOR. DEF. VI. A circle is said to be described about a rectilinear figure, when the circumference passes through each of the angular points of the figure. And the figure is said to be inscribed in the circle. PROPOSITION I. THEOREM. The line, which bisects a chord of a circle at right angles, must contain the centre. F B Let ABC be the given O. Let the st. line CE bisect the chord AB at rt. angles in D. Then the centre of the must lie in CE. For if not, let O, a pt. out of CE, be the centre ; and join OA, OD, OB. Then, in As ODA, ODB, · AD= BD, and DO is common, and OA OB ; and .. ▲ ODB is a right ▲ . But 4 CDB is a right, by construction; L ..4 ODB = ▲ CDB, which is impossible; .. O is not the centre. I. c. I. Def. 9 Thus it may be shewn that no point, out of CE, can be the centre, and.. the centre must lie in CE. COR. If CE be bisected in F, then F is the centre of the circle. PROPOSITION II. THEOREM. If any two points be taken in the circumference of a circle, the straight line, which joins them, must fall within the circle. Let A and B be any two pts. in the Oce of the ABC. Then must the st. line AB fall within the ✪. Take any pt. D in the line AB. Find the centre of the O. III. 1, Cor. I. A. 1. 16. I. 19. ..the distance of D from O is less than the radius of the O, and.. D lies within the O. And the same may be shewn of any other pt. in AB. .. AB lies entirely within the . Post. Q. E. D. |