 | Jeremiah Day - 1815 - 388 σελίδες
...a parabola about a double ordinate or base. 117. Multiply the square of the middle diameter by T»T of the axis, and the product by .7854. Ex. If the...square of the middle diameter, from the sum subtract f of the square of the difference of the diameters; and multiply the remainder by -J of the length,... | |
 | Thomas Keith - 1817 - 306 σελίδες
...frustum of a parabolic Conoid 133 XXIII. To find the solidity of a parabolic Spindle .... 134 * XXIV. To find the solidity of the middle frustum of a parabolic Spindle 135 * XXV. To find the solidity of an hyperbolic Conoid • '136 » XXVI. To find the solidity of the... | |
 | William Hawney - 1820 - 336 σελίδες
...•SA'+jMf*— f/i|i*X,3tM«AfS-S, the solidity of onefourfh of the middle frustum of the spindle. Hence To find the Solidity of the middle Frustum of a Parabolic Spindle, To twice the square of the middle diameter, add the square of the diameter of the end ; and from the... | |
 | Jeremiah Day - 1824 - 440 σελίδες
...of a parabola about a double ordinate or base. 117. Multiply the square of the middle diameter by T^ of the axis, and the product by .7854. Ex. If the...diameter 17, what is the solidity ? Ans. 3631.7, PROBLEM XV1IJ. To find the solidity of the MIDDLE FRUSTUM of a parabolic spindle. 118. Add together the square... | |
 | Thomas Curtis - 1829 - 810 σελίδες
...by the length of the spindle, and the product by -418879, and it will give the solidity. PROB. XLII. To find the solidity of the middle frustum of a parabolic spindle, whose dimensions are given. Rule. — To eight times the square of the middle diameter add three times... | |
 | Jeremiah Day - 1831 - 418 σελίδες
...a parabola about a double ordinate or base. 117. Multiply the square of the middle diameter by T"5 of the axis, and the product by .7854. Ex. If the...square of the middle diameter; from the sum subtract f of the square of the difference of the diameters, and multiply the remainder by i of the length,... | |
 | Jeremiah Day - 1831 - 520 σελίδες
...a parabola about a double ordinate or base. 117. Multiply the square of the middle diameter by T8T of the axis, and the product by .7854. Ex. If the...square of the middle diameter; from the sum subtract f of the square of the difference of the diameters, and multiply the remainder by i of the length,... | |
 | Ireland commissioners of nat. educ - 1834 - 370 σελίδες
...frustum of a parabolic conoid, ..... 182 XXIII. To find the solidity of a parabolic spindle, . 183 XXIV. To find the solidity of the middle frustum of a parabolic spindle, ..... 184 XXV. To find the solidity of an hyperbolic conoid, . 185 XXVI. To find the solidity of the... | |
 | Jeremiah Day - 1836 - 418 σελίδες
...a parabola about a double ordinate or base. 117. Multiply the square of the middle diameter by T'j of the axis, and the product by .7854 Ex. If the axis...solidity of the MIDDLE FRUSTUM of a parabolic spindle. 1 18. Add together the square of the end diameter, and twice the square of the middle diameter; from... | |
 | B[enjamin] Franklin Callender - 1836 - 226 σελίδες
...16X16=256X40=10240X41888=428.933, the solidity. SECTION XVII. Middle Frustum of a Parabolic Spindle. To find the solidity of the Middle Frustum of a Parabolic Spindle. To twice the square of the middle diameter, add the square of the diameter of the base ; from this... | |
| |
T8T of the axis, and the product by .7854. Ex. If the axis of a parabolic spindle be 30, and the middle diameter 17, what is the solidity ? Ans. 
