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" ... then multiply the second and third terms together, and divide their product by the first, the quotient will be the fourth term or answer, in the same denomination vj'ilh the third term. "
Pantology: Or, A Systematic Survey of Human Knowledge; Proposing a ... - Σελίδα 320
των Roswell Park - 1841 - 587 σελίδες
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A Treatise on Plane and Spherical Trigonometry: With Their Most Useful ...

John Bonnycastle - 1806 - 464 σελίδες
...proportion, according to the proper rule, multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term required, for the natural numbers. Or, in working by logarithms, add the logarithms of the second and...

Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain and ...

Nathan Daboll - 1813 - 244 σελίδες
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second...

Arithmetic Modernised: Or, A Complete System of Arithmetic, Adapted to ...

John Davidson, Robert Scott (writing master) - 1818 - 190 σελίδες
...must be less, write the greater as thefirst, and the other as the second proportional. The numbers being thus stated, multiply the second and third terms together, and divide their product by thefirst, the quotient will be the answer, in ihe same name in which the third term is9 when you arc...

Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1818 - 246 σελίδες
...terms to the same denomination, and reduce the second term to the lowest naiae mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term, the quotient will be the answer to the question, in fue same denomination you left the second...

A New and Concise System of Arithmetick: Containing Vulgar, Decimal, and ...

Beriah Stevens - 1822 - 436 σελίδες
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; then multiply the second and third terms together, and divide their product by the first, ami the quotient gives the answer ; which is always of the same name with the middle term. When the...

The Scholar's Arithmetic: Designed for the Use of Schools in the United States

Jacob Willetts - 1822 - 200 σελίδες
...reduce it to the vest one mentioned! 6. Then multiply the second and third term together and divide the product by the first, and the quotient will be the fourth term or answer ; which will be in the same denomination as the second, or as that to which the second was reduced....

Elements of Arithmetic

Etienne Bézout - 1824 - 238 σελίδες
...consequently, for performing the Simple Rule of Three Direct, a« explained in article (179), is as follows ; Multiply the second and third terms together and divide their product by the first ; the quotient will be the answer, or fourth term sought. -I he following examples will explain the...

The tutor's expeditious assistant; being a system of practical arithmetic ...

John White - 1826 - 128 σελίδες
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. Multiply the second and third terms together, and divide their product by the first, and their quotient will be the answer, in the same denomination as that in which the second was left. •...

The Federal Calculator: Or, A Concise System of Practical Arithmetic

William Slocomb - 1828 - 160 σελίδες
...first and third terms to the same denomination, and the second to the lowest name mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second...

The Juvenile Arithmetick, and Scholar's Guide: Wherein Theory and Practice ...

Martin Ruter - 1828 - 180 σελίδες
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together, and divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between...




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