 | Bourdon (M., Louis Pierre Marie) - 1831 - 446 σελίδες
...with reference to a certain letter, divide the fir it term on the left of the dividend by the first term on the left of the divisor, the result is the...term, and subtract the product from the dividend. Then divide the first term of the remainder by the first term of the divisor, which gives the second... | |
 | Bourdon (M., Louis Pierre Marie) - 1831 - 326 σελίδες
...dividend by the first term on the left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second term of the... | |
 | Charles Davies - 1835 - 378 σελίδες
...quotients are always arranged.. 55. Hence, for the division polynomials we have the following RULE. on the left of the divisor, the result is the first...Then divide the first term of the remainder by the fast term of the divisor, which gives the second term of the quotient ; multiply the divisor by this... | |
 | 1836 - 352 σελίδες
...divide the first term in the dividend by the first in the divisor, and write the result as the first in the quotient ; multiply the divisor by this term, and subtract the product from the dividend ; proceed to deal with the remainder, if any, in the same way. 43. By applying the same reasoning as... | |
 | 1836 - 530 σελίδες
...divide the first term in the dividend by the first in the divisor, and write the result as the first in the quotient ; multiply the divisor by this term, and subtract the product from the di6 a 6s + б Ь3 vidend ; proceed to deal with the remainder, if any, in the same way. 43. By applying... | |
 | 1839 - 368 σελίδες
...reference to a certain letter, and then divide the first term on the left of the dividend by the first term on the left of the divisor, the result is the...Then divide the first term of the remainder by the fast term of the divisor, which gives the second term of the quotient ; multiply the divisor by this... | |
 | Andrew Bell (writer on mathematics.) - 1839 - 500 σελίδες
...this quantity may stand first, and the rest in order. Divide the first term of the dividend by that of the divisor, the result is the first term of the...term, and subtract the product from the dividend. Consider the remainder as a new dividend, arrange its terms, and proceed as before ; and continue the... | |
 | Bourdon (M., Louis Pierre Marie) - 1839 - 368 σελίδες
...term on the left of the dividend by the first term on the left of the divisor, the result is the fast term of the quotient ; multiply the divisor by this...term, and subtract the product from the dividend. 1. Divide a2— 2ax + a;2 It is found most conveni in division in algebra, to p] the divisor on the... | |
 | William Scott - 1844 - 568 σελίδες
...according to the powers of the same letter. Divide the first term of the dividend by the first terra of the divisor ; the result is the first term of the...divisor by this term, and subtract the product from the quotient. . Divide the first term of the remainder by the first term of the divisor; the result is... | |
 | Davis Wasgatt Clark - 1844 - 394 σελίδες
...exponents shall diminish from left to right. 2. Divide the first term of the dividend by the first term of the divisor ; the result is the first term of the quotient. 3. Multiply the whole divisor ly this term, and subtract the product from the dividend ; the remainder... | |
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... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. 
