 | William Nicholson - 1809 - 716 σελίδες
...only one of the unknown quantities, by any of the following methods: 1" Method. In either equation, find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then only contain one nuknown quantity,... | |
 | James Wood - 1815 - 338 σελίδες
...only one of the unknown quantities, by any of the following methods : 1" Method. In either equation, find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then only contain one unknown quantity,... | |
 | William Nicholson - 1819 - 432 σελίδες
...only one of the unknown quantities, by any of the following methods : 1st Method. In either equation find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then only contain one unknown quantity,... | |
 | Miles Bland - 1821 - 898 σελίδες
...equation by 5, and the second by 2, and then, subtracting the second from the first. 2. By substitution. Find the value of one of the unknown quantities, in...obtained in which there is only one unknown quantity. Thus in the first of the preceding examples ; from the second equation, x = 16 — 4 у ; substituting... | |
 | Miles Bland - 1824 - 404 σελίδες
...equation by 5, and the second by 2, and then subtracting the second from the first. 2. By substitution. Find the value of one of the unknown quantities, in...obtained in which there is only one unknown quantity. Thus in the first of the preceding examples ; from the second equation, x = 16 — 4y ; substituting... | |
 | James Ryan, Robert Adrain - 1824 - 542 σελίδες
...it may be more convenient to solve one ot both of the equations first ; that is, to find the values of one of the unknown quantities, in terms of the other and known quantities, as before ; when the rules for eliminating unknown quantities, (§ I. Chap. IV). may be more easily... | |
 | George Lees - 1826 - 276 σελίδες
...Now, x - sy^~L?—™^H- 12 - « * •— g — g "~ 2 ~~ 86. METHOD 3d, In either equation, Jind a value of one of the unknown quantities, in terms of the other and known quantities ; substitute this value for the unknown quantity in the second equation, there will thence arise an... | |
 | John Darby (teacher of mathematics.) - 1829 - 212 σελίδες
...Indeterminate Analysis. CASE I. When the given equation contains two unknown quantities. RULE. 1 . Find the value of one of the unknown quantities in terms of the rest, as in step first, in the first example. _ 2. Divide the numerator by the denominator, if divisible,... | |
 | Peter Nicholson - 1831 - 326 σελίδες
...the possible values of x and y in integer numbers, suppose the numbers a, b, c, prime to each other. Find the value of one of the unknown quantities in terms of the other. Thus, if the equation be by-lc ax—by=c, then z= — ; Or, ax+by=c, then x= — - — • Increase... | |
 | John Radford Young - 1839 - 332 σελίδες
...each unknown quantity may be obtained by either of the three following methods. First Method. (54.) Find the value of one of the unknown quantities in terms of the other and the known quantities, from the first equation, by the method already given. Find the value of the same... | |
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Find the value of one of the unknown quantities, in terms of the other and known quantities... 
