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52. Bought 480 yds. cloth at 663 cts., and sold it at 874 cts.; what was the profit? $ of 480 = $60; }

= $420 of 480 = 160; i = 320

$100, Profit. 53. Bought 480 yds. at 374 cts., and sold it for 50 cts per yard; what was the profit ?

4 of 480 = $240 f of 480 = 60; & 180

$60, Profit.

54. Bought 600 yds. cloth at $1 per yard, and sold it for $1.25 per yard; what was the profit ? 600 x 11

$950
600 x 1

600
$150, Profit.

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55. How many yards of cloth, at 124 cts. per yard, can be bought for $240 ? 8 yds. can be bought for every dollar.

240 x 8 = 1920 yds. 56. How many yards for 16 cts. ? 20 cts. ? 25 cts. ? 374 cts. ? 50 cts. ? 621 cts.? 75 cts. ? 871 cts.?

.

80

371 = y; 240 x Š = 640 yds.;

for 624 cts. = 240 x 57. Sold 500 barrels flour at $6.624 per barrel, and invested the proceeds in different kinds of dry goods, averaging 874 cts. per yard. What were the proceeds of the flour, and how many yards of goods did I get ?

COMPARATIVE VIEW OF DENOMINATE NUM.

BERS AND FRACTIONS.

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5

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The common fraction may be reduced to a decimal ; thus, 10 = .2864583.

The denominate numbers are all reduced to the lowest denomination, and the whole number and fractions are all reduced to a common denominator.

Cor. 1.-As the number of each denomination may properly be regarded as units, so the number expressing the numerator of any fraction may be regarded as units, and used accordingly.

TIME.

PROBLEM I. To find the difference of time between two given dates, subtract the former date from the latter.

EXAMPLES.

1. What is the time from the 10th April, 1845, to the 15th July, 1850 ? yr.

da. 1850 영

15 1845 4 10

mo.

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mo.

2. What is the time between 15th July, 1850, and the 10th April, 1856? yr.

da. 1856 4 10

1850 ng 15 Ans. 5 8 25

3. What is the time from the 15th May, 1856, to the 1st January, 1860 ?

Ans. 3 yr. 7 mo. 16 da. 4. How many years, months and days from March 10th, 1872, to June 20th, 1874 ? Ans. 2 yr. 3 mo. 10 da.

5. What is the time from Sept. 13th, 1865, to April 10th, 1870 ?

Ans. 4 yr. 6 mo. 27 da. 6. What is the time from Dec. 25th, 1870, to Jan, 13th, 1875? How many days ? 1st Ans. 4 yr. 18 da.

360 x 4 = 1440

18 2d Ans. 1458 days.

PROBLEM 11.

To find the difference of time of two places whose longitudes are given.

REM.—Divide the difference of longitude by 15, and in the quotient regard degrees, minutes and seconds as hours, minutes and seconds of time.

The time must be rated from the fixed meridian, which for the world is Greenwich, England, and as the sun appears to move west, every place west of this meridian must have earlier time, at the rate of 1 hour for every 15 degrees; that is, when it is 9 o'clock A.M., at Greenwich, it is 8 A.M. 15 degrees west of Greenwich.

EXAMPLES 1. The longitude of New York is 74° 1' 6" west, and that of Cincinnati is 84° 24' west. What is the time at Cincinnati, when it is 12 o'clock, noon, at New York.

84° 24' 0"

74 1 6
15 ) 10° 22' 54" ( 0 hr. 41 min. 31$ sec.

60
622 ( 41

12 00 00
60

41 31% 22

Ans. 11 18 28%, A.M. 15

ng
60
474 ( 31%
45

24 15

2. Longitude of New York is 74° 1' 6" and St. Louis 90° 15' 10". When it is noon at New York, what is the time at St. Louis ?

90° 15' 10"

174 1 6
15 ) 16° 14' 4" (1 hr. 4 min. 564 sec.

15

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3. The longitude of Dublin is 6° 20' 30" west, and of Louisville 85° 30' west. What is the time at Louisville, when it is 2 A.M. at Dublin ?

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