 | Charles Hutton - 1807 - 464 σελίδες
...decimal '3188, Or divide it by 3'1416, for the surface. Note. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. , Ex. 1 . Required the convex superficies of a sphere, whose diameter is 7, and circumference... | |
 | Charles Hutton - 1811 - 494 σελίδες
...decimal '3183, or divide it by 3-1416, for the surface. Note. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. EX. I . Required the convex superficies of a sphere, whose diameter is 7, and circumference... | |
 | Charles Hutton - 1822 - 616 σελίδες
...decimal -3183, or divide it by -V1416, for the surface. Nate. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. Ex. 1. Required the convex superficies of a sphere, whose diameter is 7. and circumference... | |
 | Tobias Ostrander - 1833 - 172 σελίδες
...diameter of the globe and the height of the segment given. Rule— Multiply the circumference of the whole sphere by the height of the segment, and the product will be the area of the convex surface. EXAMPLES. 1. What is the area of the convex surface of a seg ment of a... | |
 | Tobias Ostrander - 1834 - 182 σελίδες
...of the globe and the height of the segment given. Rule — Multiply the circumference of the whole sphere by the height of the segment, and the product will be the area of the convex surface. EXAMPLES. t. What is the area of the convex surface of a seg ment of a... | |
 | Thomas Holliday - 1838 - 404 σελίδες
...be the solidity. Note. The convex surface may be found by multiplying the circumference of the whole sphere by the height of the segment, and the product will be the convex surface. Examples. 1. The radius A—D of the base of the segment ABC is 8 feet, and the height... | |
 | Frederick Augustus Griffiths - 1840 - 436 σελίδες
...and multiply by '3183, or divide by 3-1416. Note. — -For the surface of the Segment, or Frustrum, multiply the whole circumference of the Sphere by the height of the part required. Example. — Required the superficies of a Globe, whose diameter is 24 inches. 24X24X3-1416... | |
 | Joseph Gwilt - 1842 - 1114 σελίδες
...decimal •3183, or divide it by 3-1416 for the surface. Remark. For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. Examplel. Required the convex superficies of a sphere whose diameter is 7 and circumference... | |
 | Frederick Augustus Griffiths - 1859 - 426 σελίδες
...and multiply by -3183 ; or divide by 3-1416. .Note. — For the surface of the segment, or frustrum, multiply the whole circumference of the sphere by the height of the pait required, Example. — Required the superficies of a globe whose diameter is 24 inches. 24 X 24... | |
 | Anthony Nesbit - 1859 - 482 σελίδες
...The surface of the segment of a sphere may be found thus : Multiply the circumference of the whole sphere by the height of the segment, and the product will be the convex surface ; to which add the are;i of the base, and the sum will be the whole eurface. 2. The... | |
| |
For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required. 