 | 1801 - 658 σελίδες
.... . 9 G£$Z I4_. . Wl:cn the ends are circular, or parallel t9 thi revolving axe. _ To dovble tiie square of the middle diameter add the square of the diameter of one end ; multiply this sum by the length of the frustum, and the product by '2618 for the content.... | |
 | Samuel Webber - 1808 - 520 σελίδες
...spheroid. . CASE I. When the ends are circular, or parallel to the revoking axis. RULE.* To double the square of the middle diameter add the square of the diameter of one end ; multiply this sum by 90 •5236 12 2808 ^^^ 78 41888 iy^Url ____- -^ •c- 4^^' f -3k. 36... | |
 | Nicolas Pike - 1808 - 470 σελίδες
...globe is somewhat like a cask, two equal segments being wanting, one on each side of the axis. RULE — To twice the square of the middle diameter, add the square of the end diameter ; multiply that sum by '7S54, and that product, multiplied by one third of the length,... | |
 | Thomas Keith - 1817 - 306 σελίδες
...middle Diameter, and that of either End being given, together with the Length of the Zone. RULE *. To twice the square of the middle diameter, add the square of the diameter of the end ; multiply • Let / = AB die fi«d Hii 7 fh(. wh .,, r — a F the revolving axis J •' ' b ~ •»•... | |
 | Anthony Nesbit - 1824 - 476 σελίδες
...middle frustum of a spheroid. CASE I. When the ends are circular or parallel to the revolving axe. RULE. To twice the square of the middle diameter, add the square of the diameter of one end ; multiply the sum by the length of the frustum, and the product thence arising by .2618, for... | |
 | Thomas Curtis - 1829 - 810 σελίδες
...being given. Rule. — Case 1. When the ends are circular, or perpendicular to the fixed axis. — To twice the square of the middle diameter add the square of the diameter of either of the ends, and multiply the same by the length of the frustum, and by -2618, and the result... | |
 | John Bonnycastle - 1829 - 256 σελίδες
...the ends being given. CASE I. When the ends are circular, or parallel to the revolving axis. RULE* To twice the square of the middle diameter add the square of the diameter of either of the ends, and this sum * Demon. Let AO= a, DO= 6, E»=A, no= c, ro-= x, re =y, and p= 3.... | |
 | Ireland commissioners of nat. educ - 1834 - 370 σελίδες
...the middle diameter, and that of either end being given, together with the length of the zone. RULE. To twice the square of the middle diameter, add the square of the diameter of the end ; multiply the sum by the length of the zone, and the product again by -2618 for the solidity.* * Demonstration.... | |
 | Tobias Ostrander - 1834 - 182 σελίδες
...the ends being given : I. — When the ends are circular or parallel: to the revolving axis. Rule — To twice the square of the middle diameter add the square of the diameter of either of the ends, and this sum multiplied by the length of the frustrum, and that product by ,2618,... | |
 | B[enjamin] Franklin Callender - 1836 - 226 σελίδες
...solidity. SECTION XVII. Middle Frustum of a Parabolic Spindle. To find the solidity of the Middle Frustum of a Parabolic Spindle. To twice the square of the...middle diameter, add the square of the diameter of the base ; from this sum subtract four tenths of the square of the difference of the two diameters ; multiply... | |
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Rule: To twice the square of the middle diameter, add the square of the diameter of... 
