 | Adrien Marie Legendre, John Farrar - 1825 - 294 σελίδες
...evidently greater than CO, and CO than C/(52); for a still stronger reason CF > CL But CF — C r, since the chords AB, DE, are equal. Therefore CG >...only the point A in common with the circumference ; therefore BD is a tangent (97). 111. Scholium. We can draw through a given point A only one tangent... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 σελίδες
...through three given points. THEOREM. o 109. Two equal chords are at the same distance from the centre, and of two unequal chords the less is at the greater distance from the centre. Demonstration 1. Let the chord AB = DE (fig. 53). Bisect Fig. 53. these chords by the perpendicular... | |
 | Adrien Marie Legendre - 1825 - 276 σελίδες
...one and the same circumference. . • 109. Two equal chords are at the same distance from the centre, •and of two unequal chords the less is at the greater distance from the centre. Demonstration 1. Let the chord AB = DE (fig' 53). Bisect Fig. these chords by the perpendicular CF,... | |
 | Adrien Marie Legendre - 1828 - 346 σελίδες
...one and the same circumference. THEOREM. 109. Two equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre. First. Suppose the chord AB= DE. Bisect those chords by the perpendiculars CF, CG, and draw the radii... | |
 | Adrien Marie Legendre - 1836 - 394 σελίδες
...to be impossible. PROPOSITION VIII. THEOREM. Two equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre. 'First. Suppose the chord AB — DE. Bisect these chords by the perpendiculars CF, CG, and draw the... | |
 | Adrien Marie Legendre - 1838 - 382 σελίδες
...III. 47 PROPOSITION VIII. THEOREM. Two equal chords are equally distant from the centre ; andoftwo unequal chords, the less is at the greater distance from the centre. First. Suppose the chard AB = DE. Bisect these chords by the perpendiculars CF, CG, and draw the radii... | |
 | Adrien Marie Legendre - 1841 - 288 σελίδες
...the same circumference. THEOREM. 1 09. Two equal chords are at the same distance from the centre ; and, of two unequal chords, the less is at the greater distance from the centre. Demonstration 1. Let the chord AB — DE (fig. 53). Bisect Fig. 53. these chords by the perpendiculars... | |
 | Charles Davies - 1849 - 372 σελίδες
...points. PROPOSITION VIII. THEOREM. Two equal chords are equally distant from the centre ; andoftioo unequal chords, the less is at the greater distance from the centre. First. Suppose the chord AB = DE. Bisect these chords by the perpendiculars CF, CG, and draw the radii... | |
 | Adrien Marie Legendre - 1852 - 436 σελίδες
...to be impossible. PROPOSITION VIII. THEOEEM. Two equal chords are equally distant from the centre; and of two unequal chords, the less is at the greater distance from the centre. Suppose the chord AB to be equal to the chord DE. From C the centre of the circle, draw CF, and CG... | |
 | Charles Davies - 1854 - 436 σελίδες
...impossible. 64 GEOMETRY. * PROPOSITION VIII. THEOREM. Two equal chords are equally distant from the centre; and of two unequal chords, the less is at the greater distance from the centre, Suppose the chord AB to be equal to the chord DE. From C the centre of the circle, draw CF, and CG... | |
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Two equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre. 
