Mensuration for elementary and middle class schools1875 - 85 σελίδες |
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Σελίδα 21
... broad ? 7. A rectangle contains sq . ft . and is 10 inches broad ; find its length . 8. A room is 23 ft . 10 in . long and 25 ft . broad ; how much will it cost to cover it with carpet , at 4s . 10d . a square yard ? 9. Each side of a ...
... broad ? 7. A rectangle contains sq . ft . and is 10 inches broad ; find its length . 8. A room is 23 ft . 10 in . long and 25 ft . broad ; how much will it cost to cover it with carpet , at 4s . 10d . a square yard ? 9. Each side of a ...
Σελίδα 40
... broad , and 12 ft . high ; what would be the cost of painting it at 94d . per square yard ? 28. A pit is 25 ft . long , 15 ft . broad , and 7. ft deep ; what was the cost of digging it at 74d . per cubic yard ? 29. A rectangular log of ...
... broad , and 12 ft . high ; what would be the cost of painting it at 94d . per square yard ? 28. A pit is 25 ft . long , 15 ft . broad , and 7. ft deep ; what was the cost of digging it at 74d . per cubic yard ? 29. A rectangular log of ...
Σελίδα 55
... broad , the length of its edge 4 ft . 3 in . , and the perpendicular height 9 ft .; find its volume . 6. A frustrum of a cone is 25 ft . high , and the circumference of its greater and smaller ends 20 ft . and 10 ft . respectively ...
... broad , the length of its edge 4 ft . 3 in . , and the perpendicular height 9 ft .; find its volume . 6. A frustrum of a cone is 25 ft . high , and the circumference of its greater and smaller ends 20 ft . and 10 ft . respectively ...
Σελίδα 58
... broad , and 21⁄2 in . thick . But when built in a wall the bricks do not lie close to each other , a layer of mortar encasing them all round ; and this layer is supposed to be in . thick , so that in measuring brickwork the dimensions ...
... broad , and 21⁄2 in . thick . But when built in a wall the bricks do not lie close to each other , a layer of mortar encasing them all round ; and this layer is supposed to be in . thick , so that in measuring brickwork the dimensions ...
Σελίδα 76
... broad , and 10 ft . 8 in . high . 3. A piece of gold leaf is of an inch in thickness ; how much solid gold is there in enough of this to cover 63 square feet ? 4. Find the volume of a cylinder whose radius is 8 ft . , and height 80 ft ...
... broad , and 10 ft . 8 in . high . 3. A piece of gold leaf is of an inch in thickness ; how much solid gold is there in enough of this to cover 63 square feet ? 4. Find the volume of a cylinder whose radius is 8 ft . , and height 80 ft ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
16 Maps acres ATLAS base breadth calculating called centre chains circle circular circumference cloth lettered consisting of 32 contains exactly convex surface cube cubic foot cubic ft diagonal diameter dimensions divided ellipse Euclid EXERCISES Fcap feet field find its area find its solidity find its volume find the area find the cost find the length Find the solid find the volume frustrum GEOGRAPHY Glasgow Gunter's chain heptagon Herriot Hill hypothenuse inscribed LESSON LL.D miles multiply half number of sides ordinates parallel parallelopiped pentagonal perpendicular distance perpendicular height Physical Map pickets poles radius rectangular regular polygon rhomboid rhombus right angle right-angled triangle rule sector segment side measures slant height small faces solid content solid figure sphere is equal square and rectangle square foot square pyramid square yard straight line surveyor trapezium trapezoid triangular prism vertex wedge World-shewing
Δημοφιλή αποσπάσματα
Σελίδα 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.
Σελίδα 29 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Σελίδα 23 - RULE. From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.