Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by Numbers are Analytically Explained and Synthetically AppliedJ. Prentiss, 1810 - 180 σελίδες |
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Σελίδα 25
... cloth , each piece containing 28 yards , at 6 dollars a yard ; how many yards were there , and what was the whole cost ? Ans . The whole cost was 2184 dollars . 24. Multiply 37864 by 235 . 25 . 29831 952 . 26 . • 93956 8704 . · Product ...
... cloth , each piece containing 28 yards , at 6 dollars a yard ; how many yards were there , and what was the whole cost ? Ans . The whole cost was 2184 dollars . 24. Multiply 37864 by 235 . 25 . 29831 952 . 26 . • 93956 8704 . · Product ...
Σελίδα 29
... cloth could you buy for 30 dollars , at 5 dollars a yard ? 6. If you pay 40 dollars for 10 yards of cloth , what is one yard worth ? 7. A man works 6 days for 42 shillings ; how many shillings is that for one day ? 8. How many quarts in ...
... cloth could you buy for 30 dollars , at 5 dollars a yard ? 6. If you pay 40 dollars for 10 yards of cloth , what is one yard worth ? 7. A man works 6 days for 42 shillings ; how many shillings is that for one day ? 8. How many quarts in ...
Σελίδα 31
... cloth , at 4 dollars a yard , can be Dought for 856 dollars ? The reading used by the pupil in committing the table may be , 2 by 2 is 1 , 4 by 2 is 2 , & c .; or , 2 in 2 one time , 2 in 4 two times , & c . Here the number to be ...
... cloth , at 4 dollars a yard , can be Dought for 856 dollars ? The reading used by the pupil in committing the table may be , 2 by 2 is 1 , 4 by 2 is 2 , & c .; or , 2 in 2 one time , 2 in 4 two times , & c . Here the number to be ...
Σελίδα 33
... cloth can be bought for 4,354,560 dollars , at 3 dollars ? at 4 dollars ? at 6 dollars at 10 ? at 7 ? Note . Let the pupil be required to prove the foregoing , and al . following examples . 26. Divide 1005903360 by 2 , 3 , 4 , 5 , 6 , 7 ...
... cloth can be bought for 4,354,560 dollars , at 3 dollars ? at 4 dollars ? at 6 dollars at 10 ? at 7 ? Note . Let the pupil be required to prove the foregoing , and al . following examples . 26. Divide 1005903360 by 2 , 3 , 4 , 5 , 6 , 7 ...
Σελίδα 37
... cloth for 60 dollars ; how much was that per yard ? 15 yards are 3 X 5 yards . If there had been but 5 yards , the cost of one yard would be 60 12 dollars ; but , as there are 3 times 5 yards , the cost of one yard will evidently be but ...
... cloth for 60 dollars ; how much was that per yard ? 15 yards are 3 X 5 yards . If there had been but 5 yards , the cost of one yard would be 60 12 dollars ; but , as there are 3 times 5 yards , the cost of one yard will evidently be but ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
12 cents acres amount annexed annuity answer apples arithmetical series bushels called ciphers common difference composite number compound interest compound numbers contained cord feet cows cube root cubic decimal fractions diameter divided dividend division divisor dollars equal EXAMPLES FOR PRACTICE factors farthings federal money foot gain gallons given number greatest common divisor Hence hogshead horse hundred hundredths improper fraction inches last term least common multiple length less number measure miles mills minuend minutes mixed number months multiplicand multiply Note number of terms OPERATION oranges ounce paid pence pints pounds present worth principal proportion pupil quantity quarts quotient rate per cent ratio receive Reduce remainder right hand figure rule shillings side simple numbers sold solid feet square root subtraction subtrahend tens thousandths units vulgar fractions weight whole number write yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 90 - Divide the denominator by the whole number, when it can be done without a remainder ; otherwise, multiply the numerator by it, and under the product write the denominator, which may then be reduced to a whole or mixed number.
Σελίδα 2 - BBOWN, of the said district, hath deposited in this office the title of a book, the right whereof he claims as author, in the words following, to wit : " Sertorius : or, the Roman Patriot.
Σελίδα 95 - Prom' the very process of dividing each of the parts, that is, of increasing the denominators by multiplying them, it follows, that each denominator must be & factor of the common denominator ; now, multiplying all the denominators together will evidently produce such a number. Hence, To reduce fractions of different denominators to equivalent fractions having...
Σελίδα 139 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Σελίδα 112 - 03, the same as before. IT 73. The foregoing examples and remarks are sufficient to establish the following RULE. In the division of decimal fractions, divide as in whole numbers, and from the right hand of the quotient point off...
Σελίδα 124 - The rate of interest upon the loan or forbearance of any money, goods or things in action...
Σελίδα 83 - Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain.
Σελίδα 142 - This may be done, provided the terms be so placed, that the product of the extremes shall be equal to that of the means. 4. If 3 men perform a certain piece of work in 10 days, how long will it take 6 men to do the same ? The number of days in which 6 men will do the work being the term sought, the.
Σελίδα 166 - Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Σελίδα 63 - Thirty days hath September, April, June, and November, February twenty-eight alone ; All the rest have thirty-one.