Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by Numbers are Analytically Explained and Synthetically AppliedJ. Prentiss, 1810 - 180 σελίδες |
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Σελίδα 7
... Pound , by Inspection , the three first Decimals of a Pound to Shillings , & c . , by In- 113 115 116 spection , 117 Reduction of Currencies , 120 To reduce English , & c . Currencies to Federal Money , 122 Federal Money to the ...
... Pound , by Inspection , the three first Decimals of a Pound to Shillings , & c . , by In- 113 115 116 spection , 117 Reduction of Currencies , 120 To reduce English , & c . Currencies to Federal Money , 122 Federal Money to the ...
Σελίδα 15
... pounds , another 2156 pounds , and another 2210 pounds ; what was the amount of hay purchased ? 20. A person owes A 100 dollars , B 2160 dollars , C 785 dollars , D 92 dollars ; what is the amount of his debts ? 21. A farmer raised ...
... pounds , another 2156 pounds , and another 2210 pounds ; what was the amount of hay purchased ? 20. A person owes A 100 dollars , B 2160 dollars , C 785 dollars , D 92 dollars ; what is the amount of his debts ? 21. A farmer raised ...
Σελίδα 16
... pounds ; how much did they all weigh ? Ans . 1500 . 9. The fore quarters of an ox weigh one hundred and eight pounds each , the hind quarters weigh one hundred and twenty - four pounds each , the hide seventy - six pounds , and the ...
... pounds ; how much did they all weigh ? Ans . 1500 . 9. The fore quarters of an ox weigh one hundred and eight pounds each , the hind quarters weigh one hundred and twenty - four pounds each , the hide seventy - six pounds , and the ...
Σελίδα 22
... pounds of tea cost at 43 cents a pound ? 9. There are 24 hours in one day ; how many hours in 2 days ? in 7 days ? in 3 days ? in 4 days ? 10. Six boys met a beggar , and gave him 15 cents each ; how many cents did the beggar receive ...
... pounds of tea cost at 43 cents a pound ? 9. There are 24 hours in one day ; how many hours in 2 days ? in 7 days ? in 3 days ? in 4 days ? 10. Six boys met a beggar , and gave him 15 cents each ; how many cents did the beggar receive ...
Σελίδα 29
... pound , and 48 pounds of cheese at 7 cents a pound ; how many cents must he re- ceive in pay ? 18. A boy bought 10 oranges ; he kept 7 of them , and sold the others for 5 cents apiece ; how many cents did he receive ? 19. The ...
... pound , and 48 pounds of cheese at 7 cents a pound ; how many cents must he re- ceive in pay ? 18. A boy bought 10 oranges ; he kept 7 of them , and sold the others for 5 cents apiece ; how many cents did he receive ? 19. The ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
acres amount annexed annuity answer apples arithmetical series bushels called ciphers common difference composite number compound interest compound numbers contained cord feet cows cube root cubic decimal fractions diameter divided dividend division divisor dollars equal evidently EXAMPLES FOR PRACTICE factors farthings federal money foot gain gallons given number given sum greatest common divisor Hence hogshead horse hundred hundredths improper fraction inches last term least common multiple length less number measure miles mills minuend minutes mixed number months multiplicand multiply Note number of terms OPERATION oranges ounce paid payment pence pints pounds present worth principal proportion pupil quantity quarts quotient rate per cent ratio receive Reduce remainder right hand figure rule shillings side simple numbers sold solid feet square root subtraction subtrahend tens thousandths units vulgar fractions weight whole number write yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 90 - Divide the denominator by the whole number, when it can be done without a remainder ; otherwise, multiply the numerator by it, and under the product write the denominator, which may then be reduced to a whole or mixed number.
Σελίδα 4 - BBOWN, of the said district, hath deposited in this office the title of a book, the right whereof he claims as author, in the words following, to wit : " Sertorius : or, the Roman Patriot.
Σελίδα 95 - Prom' the very process of dividing each of the parts, that is, of increasing the denominators by multiplying them, it follows, that each denominator must be & factor of the common denominator ; now, multiplying all the denominators together will evidently produce such a number. Hence, To reduce fractions of different denominators to equivalent fractions having...
Σελίδα 139 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Σελίδα 112 - 03, the same as before. IT 73. The foregoing examples and remarks are sufficient to establish the following RULE. In the division of decimal fractions, divide as in whole numbers, and from the right hand of the quotient point off...
Σελίδα 124 - The rate of interest upon the loan or forbearance of any money, goods or things in action...
Σελίδα 83 - Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain.
Σελίδα 142 - This may be done, provided the terms be so placed, that the product of the extremes shall be equal to that of the means. 4. If 3 men perform a certain piece of work in 10 days, how long will it take 6 men to do the same ? The number of days in which 6 men will do the work being the term sought, the.
Σελίδα 166 - Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Σελίδα 63 - Thirty days hath September, April, June, and November, February twenty-eight alone ; All the rest have thirty-one.