The geometry, by T. S. Davies. Conic sections, by Stephen FenwickJ. Weale, 1853 |
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Σελίδα 8
... , DF ; Wherefore likewise the angle BAC coincides with the angle EDF , and is equal ( 8 Ax . ) to it . Therefore if two triangles , etc. Q. E. D. PROPOSITION IX . PROB . To bisect a given rectilineal 8 EUCLID'S ELEMENTS .
... , DF ; Wherefore likewise the angle BAC coincides with the angle EDF , and is equal ( 8 Ax . ) to it . Therefore if two triangles , etc. Q. E. D. PROPOSITION IX . PROB . To bisect a given rectilineal 8 EUCLID'S ELEMENTS .
Σελίδα 9
... bisect it . Take any point D in AB , and from AC cut ( 3. 1. ) off AE equal to AD ; join DE , and upon the side DE remote ... bisected by the straight line AF . Which was to be done . PROPOSITION X. B E PROB . To bisect a given finite ...
... bisect it . Take any point D in AB , and from AC cut ( 3. 1. ) off AE equal to AD ; join DE , and upon the side DE remote ... bisected by the straight line AF . Which was to be done . PROPOSITION X. B E PROB . To bisect a given finite ...
Σελίδα 10
... bisect ( 10. 1. ) FG in H , and join CF , AF CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . Because FH is equal ( Constr . ) to HG , and HC common to the two triangles ...
... bisect ( 10. 1. ) FG in H , and join CF , AF CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . Because FH is equal ( Constr . ) to HG , and HC common to the two triangles ...
Σελίδα 12
... Bisect ( 10. 1. ) AC in E , join BE and produce it to F , and make EF equal ( 3. 1. ) to BE ; join also FC , and produce ... bisected , it may be demonstrated that the angle BCG , that is ( 15. 1. ) , the angle ACD , is greater than the ...
... Bisect ( 10. 1. ) AC in E , join BE and produce it to F , and make EF equal ( 3. 1. ) to BE ; join also FC , and produce ... bisected , it may be demonstrated that the angle BCG , that is ( 15. 1. ) , the angle ACD , is greater than the ...
Σελίδα 25
... Bisect ( 10. 1. ) BC in E , join AE , and at the point E in the straight line EC make ( 23. 1. ) the angle CEF equal to D ; and through A draw ( 31.1 . ) AG parallel to EC , and through C draw CG parallel to EF : therefore FECG is a ...
... Bisect ( 10. 1. ) BC in E , join AE , and at the point E in the straight line EC make ( 23. 1. ) the angle CEF equal to D ; and through A draw ( 31.1 . ) AG parallel to EC , and through C draw CG parallel to EF : therefore FECG is a ...
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ABC is equal ABCD adjacent angles angle ABC angle BAC axis bisected centre circle ABC circumference coincide cone construction coordinate planes described Descriptive Geometry diameter dicular dihedral angles draw edges ellipse equal angles equiangular equimultiples given line given point given straight line greater hence horizontal hyperbola inclination intersection join less Let ABC Let the plane line BC lines drawn magnitudes meet multiple orthograph parabola parallel planes parallelogram parallelopiped perpen perpendicular perpendicular to MN plane MN plane of projection plane parallel plane PQ prisms profile angles profile plane projecting plane Prop Q. E. D. PROPOSITION ratio rectangle rectangle contained rectilineal figure remaining angle respectively right angles SCHOLIUM segment sides six right sphere spherical angle tangent THEOR trace triangle ABC trihedral vertex Whence Wherefore