 | Robert Simson - 1775 - 534 σελίδες
...by twice the rectangle CB, BD. A Secondly, Let AD fall with- A. out the triangle ABC : Then, becaufe the angle at D is a right angle, the angle ACB is greater d than a right angle ; . and therefore the fquare of AB is equal c to the fquares of AC, CB, and twice... | |
 | Euclid - 1781 - 552 σελίδες
...by twice the reelangle CB, BD. becondly, Let AD fall with- ' A. out the triangle ABC : Then, becaule the angle at D is a right angle, the angle ACB is greater " than a right angle ; and therefore the fquare of AB is equal c to the fquaies of AC, CB, and twice the rectangle BC, CD:... | |
 | Robert Simson - 1781 - 534 σελίδες
...AC, and twice the rectangle CB, BD ; that is, the fquare of AC alone is lefs than the fquares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. then becaufe the angle at D is a right angle, the angle ACB is greater d than a right angle ; and therefore... | |
 | Euclid, John Playfair - 1795 - 462 σελίδες
...BA by twice the reftangle CB, BD. Secondly, " Let AD fail without the triangle ABC : Then, becaufe the angle at D is a right angle, the angle ACB is greater d than a iight angle; and therefore the j ,5 1. fquare of AB is equal e to the fquares of AC, CB, and... | |
 | John Playfair, Euclid - 1804 - 468 σελίδες
...AC2 is lefs than BC2+ AB2 by 2BC.BD. Secondly, Let AD fall without the triangle ABC * : Then becaufe the angle at D is a right angle, the angle ACB is greater* than a right angle, and AB2 — e AC2+BC2-)-2BC.CD. Add BC2 to each ; then AB2+BC2— AC2+2BC2+2BC.CD. But aii-ib 7. i.... | |
 | Robert Simson - 1804 - 530 σελίδες
...AC, and twice the rectangle CB, BD; that is, the fquare of AC alone is lefs than the fquares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. then becaufe the angle at D is a right angle, the a,ngle ACB is greater d than a right angle; and therefore... | |
 | John Playfair - 1806 - 320 σελίδες
...BDS+AD2=AB», and CD* +DAZ=CAC*; therefore BC2+ AB2=2BC.BD+AC2; that is, AC2 is less than BC2+ABS by 2BC.BD. Secondly, let AD fall without the triangle ABC* ;...the angle at D is a right angle, the angle ACB is greater11 than a right angle, and AB*=e AC2-)-BC2+2BC.CD. d 16. 1. Add BCz to each ; then ABS+BC2=AC24^BC?£2BC.CD.... | |
 | Robert Simson - 1806 - 546 σελίδες
...less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD fall with- - A out the triangle ABC : then, because the angle at D is a right // ' angle, the angle ACB is greater // ' d 16. 1. d ihan a right angle ; and there e 12. 2. fore the square of AB is equal* to the squares... | |
 | Euclid - 1810 - 554 σελίδες
...that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. A Secondly, Let AD fall without the triangle ABC : then,...angle at D is a right angle, the angle ACB is greater d 16. 1. •'•. than a right angle ; and theree 12. 2. fore the square of AB is equal « to the squares... | |
 | Euclides - 1814 - 560 σελίδες
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD...angle at D is a right angle, the angle ACB is greater d than a right angle ; and therefore the square of AB is equal e to the squares of AC, CB,and twice... | |
| |
CB, BA, by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i. 
