8900 at 19 facit 704 II 8 720 26 .: CASE 4. When the given price of an integer is any number of shillings under 20; RULE. Multiply the quantity by the price for the answer ia shil. lings; Or, If the price be even shillings, multiply by half the price, and double the first figure of the product for shillings; the rest of the product will be pounds; or, Work by aliquot parts. EXAMPL e-s.. 1 486 bushels at 25. per bushel. - 486 zlo 486 486 400 CASE 5. When the given price of an integer is shillings and pence, or shillings, pence and farthings; RULE. EXAMP L E s. 10 CASE 6. When the price of an integer is pounds ; or pounds, shil. hings, & . "RULE RULE. Multiply the quantity by the pounds, and with the product add the amount at the remaining part of the price, found as before: Or, Multiply the quantity by the shillings of the price, and take parts for the rest. - Ex A M P L E s. 1 428 tons, at 3!. 45. 6d. per ton. £.1381 3 10 for s. d. 2 26 at 11 14 0 cit 304 4 0 3 36 at 5 13 0 ..203 8 0 148 16 8 . 5200 o 64.98 192 10 1000 at 69 11S. CASE 7. When both the price of an integer, and the quantity, arc of divers denominations ; RULE. Multiply the price by the integers of the quantity, and take parts of the price for those of the integer. G 2 |