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4375 at 23s.

-

CASE 9th. When the price is an aliquot part of a £ Consider the given quantity as pounds, which divide by the denominator of the given aliquot part.

s d £

Examples.

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S d

6 8=4/374 at 6s. 8d. 5 011735 at 5s. 2 6=116732at2s6d

10 s. d

£124 13 4
s. d.

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100. 496 at 10 0

101.

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475 at 5 0

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4731 at 3 4

105

874 at 2 6

106. 347 at 2 0

107.

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1711 at 1 4

109. 893 at 1 3

110.

1431 at 1 0

111.

893 at 10

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4 117.

1321 at 34

CASE 10th. When the price is the complement of a pound. Subtract the given price from a pound, and divide the quantity by the denominator of such aliquot part of a pound as this remainder may be of the same, which subtract from the given quantity, considered as pounds.

Examples.

$ d £1719 at 16s 8ds a £496 at 15s. s d 119 16 8 5 0124

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136. 3421 at 19 101137. 3135 at 19 11

94. When the price is 11s. multiply by 11, as taught in Multiplication,

and divide the product by 20.

138. 2843 at19 11

CASE 11th. When the price is an aliquant part of a pound. Separate the given price into such parts of a pound as may best answer, and divide the given quantity considered as pounds, by the denominators of those parts, the sum of the quotients will be the answer.

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149. 2s Id being an aliquot part of £10, therefore add a cipher to the

given quantity, and divide b 12 and 8.

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Consider the given quantity as pounds, then multiply by the pounds of the price, and for the shillings and pence proceed as in the former case, the several quotients and first product added together, will be the answer.

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NOTE.-When the price is 17 with any number of shillings and pence annexed, the multiplication by the unit may be omitted, and the given quantity added in as pounds.

£ s d

£ s d

£ s d

188. 1273 at 1
945 at 3

191.

194.

14 14 189. 4314 at 1 16 11 13 0° 192. 8641 at 7 15 0

14 195.

749 at 5 13 9

973 at 4
197. 1045 at 9 15 6 198.

873 at 7 7 10

187.641 at 1 7 2 190.736 at 1 15 6 193. 895 at 2 13 1 196, 627 at 2 16 6 CASE 13th.-When the price is an aliquot part of 107 or 100/ Add or suppose to have added a cipher or ciphers to the given quantity considered as pounds, and divide by the denominator of the given aliquot part.

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16 8

203. 415 at

3

6 8 204.

1321 at 8

6 8

0 0

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202. 373 at 33 205.821 at 25 208. 673 at 16 13 4 211.865 at 12 10 0 214. 521 at 3 26 217. 485 at 016 8 220. 397 at 0 8 4 CASE 14th-When the given quantity is of divers denominations, and the price of one of the highest given.

221. 317 at 0 63 222.

Find the price of the highest denomination by such of the former rules as best answers, adding thereto the proportional part or parts of the price of the broken quantity, the sum will be the answer.

Or multiply the given price as in Compound Multiplication, by the highest denomination of the given quantity, adding thereto as before,

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