1. What is the sum of the three following sticks of timber, viz. the 1st. 3 tons, 49 ft. 1672 inches; the 2d, 4 tons, 47 ft. and 1000 in.; the 3d, 6 tons, 40 ft. 1001 in. Ans. 15 tons, 38 ft. 217 in. 2. Add together the following parcels, viz. 29 tons, 30 ft.; 56 tons, 39 ft.; 127 in.; 61 tons, 19 ft.; and 71 tons, 27 ft. 1649 in. Ans. 219 tons, 36 ft. 48 inch. WOOD AND BARK MEASURE. Wood and bark are bought and sold by the cord or foot; a foot of wood or bark contains 16 solid feet, or one eighth of a cord. 1728 Inches make 16 Solid Feet 128 Solid Feet Cords. feet. in. 9 127 1642 Cords. feet. in.. 64 90 146 114 33 625 154 73 407 Practical Questions in Wood and Bark Measure. 1: Add together the following parcels of wood viz. 64 cords, 120 feet; 72 cords, 21 feet; and 122 cords. Ans. 259 cords, 13 s. ft. C 2. Add 3 cords 4 feet, of wood, 12 solid feet; 6 cords 5 feet of wood, and 12 solid feet; 9 cords and 6 feet of wood together. Ans. 20 cords, 8 s. ft. DRY MEASURE. By this measure is bought and sold salt, corn, and all kinds of grain;. 268.8 solid or cubic inches make one gallon of corn, &c. ht. qt. Examples. gal. pk. pk. bu. gr. ch. $654242 Ch. bu. pks. gal. gls. pts. 32 2 1 2 (0 52312 710970 24 1 010 1106 7 3 0 2 0 Practical Questions in Dry Measure. 1. Add together the following parcels, viz. 1627 bushels, 3 pks. 7 qts. 1 pt.; 972 bu. 2 pks. 1 qt.; 2471 bu. 1 pk. 2 qts. 1 pt. Ans. 5071 bu. 3 pks. 3 qts. 2. The following quantities of coal were sold to a Merchant, viz. 41 chal. 30 bu. 3 pks.; 51 chal. 35 bu. 1 pk.; and 60 chal. 7 bu.; what was the quantity sold? Ans. 154 chal. 1 bu. O pk. CLOTH MEASURE. By this measure is bought and sold cloths and silks, &c. Practical Questions in Cloth Measure. 1. Add together the following pieces of cloth, viz. 29 yds. 3 qr. 2 na.; 30 yds. 1 qr. 3 na.; 36 yds. 1 qr. 1 na.; and another piece containing as much as all the others. Ans. 193 yds. 1 qr. 2. How many French ells in the following pieces of cloth, viz. first 22 qr. 3 na.; second 31 qr. 1 na.; third 50 qr. 2 na.; and fourth 91 qr. 1 na.? Ans. 32 F. ells. 3 qr. 3 na. OF TIME. Time is divided into seconds, minutes, hours, days, weeks, months and years. make 1 Minute. marked sc. m. 60 Seconds 60 Minutes 66 1 Hour. 1 Lunar yeaf. " 365 Days 5 hours, 48 minutes, 57 seconds, } make 1 Solar year. mo. year. year. NOTE. When any year can be divided by 4 without a remainder, it is leap year; and February has 29 days. EXAM.-A. D. 1808÷4452 and was leap year Practical Questions in Time. 1. Add together 12 years, 6 mo. 3 w. 6 d. 23 h. 12 m. 12 s.; 49 years, 5 mo. 2 w. 4 d. 12 h. 9 m.; 1 year, 9 mo. 1 w. 1 id. 1 h. 6 m. Ans. 63 yrs. 8 mo. 3 w. 5 d. 12 h. 27 m. 12 s. 2. Add 21 yrs. 9 mo. 6 d.; 31 yrs. 6 mo. 21 d.; 6 yrs, 4 mo. 9 d.; and 12 yrs. 7 mo. 10 d. together. Ans. 72 yrs. 1 mo. 18. d. COMPOUND SUBTRACTION. DEFINITION.-Compound Subtraction teaches to find the difference between a larger and a smaller number, which have several denominations. RULE. Write down the largest of the two numbers, and under it write down the smallest; observing to place every denomination under that of the same name; dollars under dollars, &c.; begin to subtract in the lowest denomination, take the lower from the upper line; if any particular figure in the lower line in any of the denominations, is larger than the one over it, subtract the lower figure from the number that it takes of this, to make one of the next higher denomination; and to the remainder add the top figure, and set the sum down, and carry one to the next denomination; proceed thus through all the denominations.s PROOF. Add together the remainder and lower line, carry as in Compound Addition; the sum will be like the upper line if the work is right. Practical Questions in American Money. 1. A man lent 3 E. 3 dolls. 3 d. 3 c.; and received 2 E. 2 dolls. 99 cts. and 9 mills; How much remains due? Ans. 10 dolls. 33 cts. 1 m. 2. A man had an estate valued at 3505 dolls. 6 d. 3 cts. 2 m.; he had three sons, to each of whom he gave 504 dolls. 5 cts. 2 m.; he also gave to two daughters, 75 dolls. 75 cts. each; What had he left? Ans. 1841 dolls. 97 cts. 6 m. 3. A man was worth 9472 dolls. 65 cts. ; by a misfortune at sea, he lost 4549 dolls. 75 cts; what was he worth after he sustained the loss ? |