By the Traverse Table. The difference of latitude and distance being found, as before, under the course 6 points, the difference of longitude 1839 is found in the departure column; under the same course, against 76, the meridional difference of latitude, taken as difference of latitude. 8. A ship in latitude 36° 20′ S, by observation, meets another ship, that had made 210 miles easting or departure from Cape Lagulhas. What is her present longitude, and also the bearing and distance of the Cape? Solution by Middle Latitude Sailing. Cape Lagullas lat. 34° 44′ S. Long. 20° 32′ E. Ship's latitude 36 30 The line AE will be the difference of longitude, the angle CDA the course or bearing of the Cape, and the line DA the distance, Computation. To find the course or bearing by plane sailing. Longitude of Cape Lagulhas Difference of longitude E. from the Cape Ship's longitude 9'91050 10'00000 2.32222 241172 32' E. 4 13 24 50 E. By By the Traverse Table. Seek difference of latitude 96, and departure 2ìò, in the table; the nearest found are 976 and 209'4, which correspond with 65° course, and 231 distance. Again, with comiddle latitude 54° as course, and 210 departure, is found 260 difference of longitude in the colúmn of The bearing and distance are found by plane sailing, as The bearing and distance being found, as already shewn; under the same course with 118 as difference of latitude, is found departure or difference of longitude 254. The difference in these results is owing to the odd minutes in the course being rejected. EXAMPLE OF A TRAVERSE. Suppose a ship to sail from latitude 43° 25′ N. on the following courses, viz. SWbS. 63 miles, SSW W. 45 miles, SbE. 54 miles, and SW6W. 74 miles. Required the latitude arrived at, and the difference of longitude made good. Solution by Middle Latitude Sailing. The difference of latitude and difference of longitude, corresponding to each course and distance, are found to be as in the following table. VOL. II. U U Courses, |