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SIMPLE NUMBERS.

1. One tenth of 6 is
2. One tenth of 46 is
3. One tenth of 300 is

1 tenth of 40 is

1 tenth of 25 is

1 tenth of 325 is

number is oneth of the

4. One half of 1 tenth of a number. One third of 1 tenth of a number =

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5. One third of 1 hundredth of a number is one th of the number. One fourth of 1 hundredth of a number

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(f) Divide 972 by 300. (h) Divide 895 by 500.

(g) Divide 972 by 400.
(i) Divide 976 by 800.

REVIEW.

6. Common multiples of 15 and 6 are The least common multiple of 15 and 6 is

7. The prime factors of 63 are (j) What are the prime factors of 124? 8. 3, 3, and 5 are the prime factors of is exactly divisible by 3; by 5; by

(1)

and
(k) Of 178?

etc.

Forty-five

-; by

(m)

12)1584 cu. ft.

(n)

(0)

160 sq. rd.)2400 sq. rd.

15)2445 sq. rd.

128 cu. feet.)1536 cu. ft.

COMMON FRACTIONS.

1. Add and . The 1. c. m. of 15 and 6 is

(a) Find the sum of 4567, 341, 245%, and 564.

2. From 92 subtract 45. 11

=

30°

(b) Find the difference of 4275 and 1328%.

3. Multiply by 9. This means

3*

(c) Find the product of 4537 multiplied by 9.

1.

13*

8*

4. Multiply 2 by . This means
(d) Find the product of 4583 multiplied by
5. Multiply 17 by 3. This means
(e) Find the product of 741 multiplied by 2.
6. Multiply 17 by 23. This means
(f) Find the product of 741 multiplied by 23.
7. Multiply 16 by 21. This means
(g) Find the product of 732

16*

30

22*

multiplied by 24.

Change 8 to

8. Divide 8 by 3. (4)* (h) Find the quotient of 97 9. Divide by 1. (9)* (i) Find the quotient of 311 10. Divide 7 by 2}. (j) Find the quotient of 55

-ths.

divided by 3. Story.

Change to

-ths.

divided by. Story.

(14)*

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divided by 23. Story.

11. Divide $1 (3) by 4. This means — (k) Find the quotient of 74 divided by 8.

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*These figures refer to notes on pages 6 and 7. See also foot-notes, page 62.

DECIMAL FRACTIONS.

1. One tenth of $6 is

.1 of $6.25 is

2. One hundredth of $6 is

.01 of $6.25 is $.0625.

3. Read each of the following in two ways: $.2436,* $.0532, $.6403, $.0042, $.0002, $.6042, $.8002.

(a) Multiply $6.25 by 4.23. This means, find 4 times

$6.25 +2 tenths of $6.25 +3 hundredths of $6.25.

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(b) Multiply $7.35 by 3.46; (c) $4.45 by 5.24.

* (1) 24¢, 3 m., and 6 tenths of a mill. (2) 2436 ten-thousandths of a dollar. †TO THE TEACHER.-Read the foot-note on page 133; also, the first part of page 143. If the pupil finds difficulty in "pointing off," teach him to use a separatrix in the multiplicand as suggested on page 133. While multiplying 6.25 by 3 hundredths, it may appear V06.25 on the slate thus:

4.23 Do not at this stage of the work allow the pupil to "point off" by counting the decimal places in the multiplicand and multiplier. Rather, lead him to think the meaning of the problem. See foot-notes, page 53.

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* 1860 lbs. at 14 a pound would be worth $18.60; at a cent a pound the value is of $18.60, or

†To divide 627 ft. by 16 ft., change both numbers to halves. See page 7, notę (20).

MEASUREMENTS.

1. A piece of land 10 rods by 16 rods contains square rods.

It is

acre.

2. A piece of land 20 rods by 16 rods contains square rods. It is

acres.

(a) Change 640 sq. rd. to acres. (b) Change 1280 sq. rd. to acres. (c) How many acres in a piece of land 40 rods by 64 rods?

acre.

rods.

3. Eighty square rods are

4. Forty square rods are

5. One hundred twenty square rods are

of an acre.

of an acre.

of an

square

6. A piece of land 20 rd. by 26 rd. contains

(d) How many acres in a piece of land 20 rd. by 26 rd.?

Find the number of acres in each of the following:

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7. A pile of wood 8 ft. by 4 ft. by 4 ft. contains cubic feet. It is

cord.

8. Sixty-four cubic feet are

9. Thirty-two cubic feet are

of a cord.

of a cord.

(k) How many cubic feet in a pile of wood 12 ft. by 8 ft. by 4 ft.?

(1) How many cords in a pile 12 ft. by 8 ft. by 4 ft.?

Find the number of cords in each of the following:
(m) 6 feet by 4 feet by 8 feet.
(0) 6 feet by 12 feet by 4 feet.

(n) 6 ft. by 8 ft. by 8 ft.
(p) 6 ft. by 12 ft. by 8 ft.

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