The Elements of Euclid for the Use of Schools and Colleges: Comprising the First Six Books and Portions of the Eleventh and Twelfth Books : with Notes, Appendix, and ExercisesMacmillan and Company, 1867 - 400 σελίδες |
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Αποτελέσματα 6 - 10 από τα 54.
Σελίδα 48
... COROLLARY . From this it is manifest , how to a given straight line , to apply a parallelogram , which shall have an angle equal to a given rectilineal angle , and shall be equal to a given rectilineal figure ; namely , by applying to ...
... COROLLARY . From this it is manifest , how to a given straight line , to apply a parallelogram , which shall have an angle equal to a given rectilineal angle , and shall be equal to a given rectilineal figure ; namely , by applying to ...
Σελίδα 49
... straight line AB . Q.E.F. COROLLARY . From the demonstration it is manifest that every parallelogram which has one right angle has all its angles right angles . PROPOSITION 47. THEOREM . In any right - angled triangle BOOK I. 46 . 49.
... straight line AB . Q.E.F. COROLLARY . From the demonstration it is manifest that every parallelogram which has one right angle has all its angles right angles . PROPOSITION 47. THEOREM . In any right - angled triangle BOOK I. 46 . 49.
Σελίδα 56
... COROLLARY . From the demonstration it is manifest , that parallellograms about the diameter of a square are likewise squares . PROPOSITION 5 . THEOREM . If a straight line be divided into two equal parts and also into two unequal parts ...
... COROLLARY . From the demonstration it is manifest , that parallellograms about the diameter of a square are likewise squares . PROPOSITION 5 . THEOREM . If a straight line be divided into two equal parts and also into two unequal parts ...
Σελίδα 57
... Corollary . and DF together with CH is the gnomon CMG ; therefore the gnomon CMG is equal to the rectangle AD , DB . To each of these add LG , which is equal to the square on CD . [ II . 4 , Corollary , and I. 34 . Therefore the ...
... Corollary . and DF together with CH is the gnomon CMG ; therefore the gnomon CMG is equal to the rectangle AD , DB . To each of these add LG , which is equal to the square on CD . [ II . 4 , Corollary , and I. 34 . Therefore the ...
Σελίδα 58
... Corollary . Therefore the rectangle AD , DB is equal to the gnomon CMG . [ Axiom 1 . To each of these add LG , which is equal to the square on CB . [ II . 4 , Corollary , and I. 34 . Therefore the rectangle AD , DB , together with the ...
... Corollary . Therefore the rectangle AD , DB is equal to the gnomon CMG . [ Axiom 1 . To each of these add LG , which is equal to the square on CB . [ II . 4 , Corollary , and I. 34 . Therefore the rectangle AD , DB , together with the ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD AC is equal angle ABC angle ACB angle BAC angle EDF angles equal Axiom base BC bisects the angle centre chord circle ABC circle described circumference Construction Corollary describe a circle diameter double draw a straight equal angles equal to F equiangular equilateral equimultiples Euclid Euclid's Elements exterior angle given circle given point given straight line gnomon Hypothesis inscribed intersect isosceles triangle less Let ABC magnitudes middle point multiple opposite angles opposite sides parallelogram perpendicular plane polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION quadrilateral rectangle contained rectilineal figure remaining angle rhombus right angles right-angled triangle segment shew shewn side BC square on AC straight line &c straight line drawn tangent THEOREM touches the circle triangle ABC triangle DEF twice the rectangle vertex Wherefore
Δημοφιλή αποσπάσματα
Σελίδα 35 - IF a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are equal to two right angles.
Σελίδα 67 - In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side subtending the obtuse angle, is greater than the squares on the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse angle, Let ABC be an obtuse-angled triangle, having the obtuse angle...
Σελίδα 73 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a Right Angle; and the straight line which stands on the other is called a Perpendicular to it.
Σελίδα 284 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 50 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Σελίδα 57 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Σελίδα 10 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Σελίδα 227 - If two straight lines be at right angles to the same plane, they shall be parallel to one another. Let the straight lines AB, CD be at right angles to the same plane : AB is parallel to CD.
Σελίδα 102 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Σελίδα 352 - Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle by the rectangle contained by the segments of the base : and conversely.