An Introduction to Algebra: Upon the Inductive Method of InstructionHilliard, Gray & Company, 1837 - 276 σελίδες |
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Σελίδα 47
... hence it was neces- sary to add the two equations together in order to make the y disappear , or as it is sometimes called , to eliminate y . 3. A market - woman sells to one person , 3 quinces and 4 melons for 25 cents , and to another ...
... hence it was neces- sary to add the two equations together in order to make the y disappear , or as it is sometimes called , to eliminate y . 3. A market - woman sells to one person , 3 quinces and 4 melons for 25 cents , and to another ...
Σελίδα 50
... hence I shall be only twice as old as you . ent ages . 2 " " their ages , says A to you were , and 4 years Required their pres- 20. There is a certain fishing rod , consisting of two parts , the upper of which is to the lower as 5 to 7 ...
... hence I shall be only twice as old as you . ent ages . 2 " " their ages , says A to you were , and 4 years Required their pres- 20. There is a certain fishing rod , consisting of two parts , the upper of which is to the lower as 5 to 7 ...
Σελίδα 55
... Hence α 2 b is the same as 2 ab 2 This is easily seen in numbers . See below , where 55 and 13 are substituted for a and b . Hence it appears , that the less part is found by subtracting half of the excess of the greater above the less ...
... Hence α 2 b is the same as 2 ab 2 This is easily seen in numbers . See below , where 55 and 13 are substituted for a and b . Hence it appears , that the less part is found by subtracting half of the excess of the greater above the less ...
Σελίδα 62
... Hence the ― part of Since a fraction is divided by dividing its numerator , the ma m + n + p will be found by dividing the numerator a multiplied by m is m a , therefore , m a divided by a m a is and , m m + n + p m + n + p n the - part ...
... Hence the ― part of Since a fraction is divided by dividing its numerator , the ma m + n + p will be found by dividing the numerator a multiplied by m is m a , therefore , m a divided by a m a is and , m m + n + p m + n + p n the - part ...
Σελίδα 63
... Hence we have x + = 472 100 100 x 18 x = 47200 118x = 47200 x = $ 400 The sum lent . It is a custom established among mathematicians to use the first letters of the alphabet for known quantities , and some of the last letters for ...
... Hence we have x + = 472 100 100 x 18 x = 47200 118x = 47200 x = $ 400 The sum lent . It is a custom established among mathematicians to use the first letters of the alphabet for known quantities , and some of the last letters for ...
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Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1826 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
An Introduction to Algebra upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1844 |
Συχνά εμφανιζόμενοι όροι και φράσεις
12 rods 3d power 3d root 5th power a b c A's share a² b² a² b³ ac² added algebra algebraic quantities apples approximate root Arith arithmetic becomes binomial Binomial Theorem bought breadth bushels coefficient compound interest compound quantities consisting contained decimal difference divide the number dividend division divisor equal equation example exponent expression factor figure formula fourth fraction gallons gives greater Hence length less Let the learner letter logarithm merator miles multiplicand negative quantity number of terms observe pears question quotient remainder required to find rule second power second root second term shillings sold subtracted Suppose third power third root twice unknown quantity whole number yards zero
Δημοφιλή αποσπάσματα
Σελίδα 186 - The 3d power of (2 a — rf)4 is (2a — rf)^«+« = (2a — d)4x3=(2a — d)". That is, any quantity, which is already a power of a compound quantity, may be raised to any power by multiplying its exponent by the exponent of the power to which it is to be raised. 7. Express the 2d power of (3 b — c)4. 8. Express the 3d power of (a — c -J- 2 d)*. 9. Express the 7th power of (2 a* — 4 c3)3.
Σελίδα 2 - DISTRICT OF MASSACHUSETTS, TO WIT: District Clerk's Office. BE IT REMEMBERED, that on the...
Σελίδα 101 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Σελίδα 92 - It will be seen by the above section that if both the numerator and denominator be multiplied by the same number, the value of the fraction will not be altered...
Σελίδα 2 - District Clerk's Office. BE IT REMEMBERED, That on the seventh day of May, AD 1828, in the fifty-second year of the Independence of the UNITED STATES OF AMERICA, SG Goodrich, of the said District, has deposited in this office the...
Σελίδα 21 - A cask, which held 146 gallons, was filled with a mixture of brandy, wine, and water. In it there were 15 gallons of wine more than there were of brandy, and as much water as both wine and brandy. What quantity was there of each...
Σελίδα 232 - I, n, d, and. S; any three of which being given, the other two may be found, by combining the two equations. I shall leave the learner to trace these ' himself as occasion may require. Examples in Progression by Difference.
Σελίδα 35 - How many days did he work, and how many days was he idle ? Let x = the number of days he worked.
Σελίδα 229 - Hence, any term may be found by adding the product of the common difference by the number of terms less one, to the first term.
Σελίδα 273 - A gentleman bought a rectangular lot of valuable land, giving 10 dollars for every foot in the perimeter. If the same quantity had been in a square, and he had bought it in the same way, it would have cost him $33 less ; and if he had bought a square piece of the same perimeter he would have had 12^ rods more.