A Popular Course of Pure and Mixed Mathematics ...: With Tables of Logarithms, and Numerous Questions for ExerciseG. B. Whittaker, 1825 - 372 σελίδες |
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Αποτελέσματα 6 - 10 από τα 100.
Σελίδα 8
... Multiply each term of the compound factor by the simple factor , as in the last case , and the result will be the product required . Examples . 2 ვის 4a - 1 2ac + d 3x - 12a2b - 8 a3c + 4ad 12 ax 2x2 + 4 3 7x2 - 4 × +4 a 3 a 12a3 4 ...
... Multiply each term of the compound factor by the simple factor , as in the last case , and the result will be the product required . Examples . 2 ვის 4a - 1 2ac + d 3x - 12a2b - 8 a3c + 4ad 12 ax 2x2 + 4 3 7x2 - 4 × +4 a 3 a 12a3 4 ...
Σελίδα 9
... Multiply 10ac by 2a . 3. Multiply 3a - 26 by 3b . 8. Multiply 3a +26 by 3a - 2b . 4. Multiply xxy + ys by x + y . 5. Multiply a + a2b + ab2 + b3 by a➡b . 6. Multiply a2 + ab + b2 by a2 — ab + b2 . 7. Multiply 3x - 2xy + 5 by x2 + 2xy ...
... Multiply 10ac by 2a . 3. Multiply 3a - 26 by 3b . 8. Multiply 3a +26 by 3a - 2b . 4. Multiply xxy + ys by x + y . 5. Multiply a + a2b + ab2 + b3 by a➡b . 6. Multiply a2 + ab + b2 by a2 — ab + b2 . 7. Multiply 3x - 2xy + 5 by x2 + 2xy ...
Σελίδα 10
... multiplication , and consequently the four following rules must be attended to . 1. That if the dividend and divisor be like , then the sign of the quotient will be + if on the contrary unlike , then the sign of the quotient will be ...
... multiplication , and consequently the four following rules must be attended to . 1. That if the dividend and divisor be like , then the sign of the quotient will be + if on the contrary unlike , then the sign of the quotient will be ...
Σελίδα 11
... Multiply and subtract as before , and the remainder is ab2 . 7. Bring down the last term of the dividend — b3 . 8. a is contained in ab2 , + ba times ; put this in the quotient . 9. Multiply and subtract as before , and nothing remains ...
... Multiply and subtract as before , and the remainder is ab2 . 7. Bring down the last term of the dividend — b3 . 8. a is contained in ab2 , + ba times ; put this in the quotient . 9. Multiply and subtract as before , and nothing remains ...
Σελίδα 12
... Multiply the integer by the denominator of the fraction , and to the product annex the numerator with its proper sign ; under this same place the former denominator , and the result will give the improper fraction required . Reduce 3a + ...
... Multiply the integer by the denominator of the fraction , and to the product annex the numerator with its proper sign ; under this same place the former denominator , and the result will give the improper fraction required . Reduce 3a + ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
ABC is equal altitude angle ABC angle BAC axis bisected centre circle ABCD circumference co-efficient cone conic section convergency curve cylinder described diameter divided draw equal angles equation equiangular equimultiples factors fluxion fore fraction geometrical progression given straight line gnomon greater Hence hyperbola join less Let ABC magnitudes multiple opposite parabola parallel parallelogram perpendicular plane angles polygon prism produced proportional pyramid Q. E. D. PROP Q. E. D. Proposition radius rectangle rectangle contained rectilineal figure remaining angle right angles segment shewn side BC similar sine solid angle solid parallelopiped spherical triangle square of AC subtract surd tang tangent Theorem third tiple triangle ABC vertex whence Wherefore
Δημοφιλή αποσπάσματα
Σελίδα 172 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle. Let...
Σελίδα 191 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Σελίδα 190 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Σελίδα 196 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Σελίδα 192 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together •with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced.
Σελίδα 177 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Σελίδα 209 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Σελίδα 284 - The bases of a cylinder are the circles described by the two revolving opposite sides of the parallelogram.
Σελίδα 286 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Σελίδα 179 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.