Modern Methods in Elementary GeometryMacmillan, 1868 - 112 σελίδες |
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Σελίδα 17
... draw A'D perpendicular to B'C ' produced , if necessary , and take DE = DC ' . Then because AC = A'C ' , these lines must be equally remote from the perpendicular A'D . Hence AC must meet B'C ' either in C ' 2 THE STRAIGHT LINE .: 17.
... draw A'D perpendicular to B'C ' produced , if necessary , and take DE = DC ' . Then because AC = A'C ' , these lines must be equally remote from the perpendicular A'D . Hence AC must meet B'C ' either in C ' 2 THE STRAIGHT LINE .: 17.
Σελίδα 18
... drawn for A ' to B'C ' . Hence if the angles C and C ' be both acute or both ob- tuse , or if either of them be a right angle , the triangles are congruent . COR . 1. If the angle C be not equal to C ' , it is sup- plementary to it ...
... drawn for A ' to B'C ' . Hence if the angles C and C ' be both acute or both ob- tuse , or if either of them be a right angle , the triangles are congruent . COR . 1. If the angle C be not equal to C ' , it is sup- plementary to it ...
Σελίδα 20
... angles , and the interior angles to twice as many right angles as the figure has sides , diminished by four right angles . D B ' E Let ABCDE be any convex polygon . B Through any point O draw OB ' , OC ' 20 ELEMENTARY GEOMETRY .
... angles , and the interior angles to twice as many right angles as the figure has sides , diminished by four right angles . D B ' E Let ABCDE be any convex polygon . B Through any point O draw OB ' , OC ' 20 ELEMENTARY GEOMETRY .
Σελίδα 21
E. M. Reynolds. Through any point O draw OB ' , OC ' , OD ' , OE ' , OA ' , parallel to the sides of the polygon ... drawn perpendicular to AB . Then every point on CD is equally distant from A and from B. For if P be any point on CD ...
E. M. Reynolds. Through any point O draw OB ' , OC ' , OD ' , OE ' , OA ' , parallel to the sides of the polygon ... drawn perpendicular to AB . Then every point on CD is equally distant from A and from B. For if P be any point on CD ...
Σελίδα 23
... draw PE , PF dicular to AB , and to AC . Then in the triangles PAE , PAF , perpen- PAE = PAF , AEP = AFP , and AP is common . Therefore PE = PF . [ I. 15 . Also no point not in AD can be equally distant from AB and from AC . Let G be a ...
... draw PE , PF dicular to AB , and to AC . Then in the triangles PAE , PAF , perpen- PAE = PAF , AEP = AFP , and AP is common . Therefore PE = PF . [ I. 15 . Also no point not in AD can be equally distant from AB and from AC . Let G be a ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
A'BC Algebra alternate angle altitude ARITHMETIC base BEGINNERS bisect BROOKE FOSS WESTCOTT Cambridge centre chord Christ's College circle touching Clifton College cloth coincide congruent CONIC SECTIONS construct contains convex angle Crown 8vo describe a circle diagonals diameter dicular distance divide Edward Thring ELEMENTARY TREATISE equal angles equally distant equiangular equilateral triangle Examination Papers Exercises exterior angle Fcap Fellow of St GEOMETRY given angle given circle given line given point given square given straight line greater Greek Text Head Master Hence inscribe intersect John's College Join JOSEPH WOLSTENHOLME Jugurtha late Fellow Latin Let ABCD line drawn locus Mathematical Lecturer measure middle point MIXED MATHEMATICS parallel to BC parallelogram perpen perpendicular polygon problems quadrilateral figure radius rectangle right angles Second Edition segments Shew similar triangles student tangent THEOREM Third Edition Thucydides trapezium triangle ABC vertex
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