Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
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Αποτελέσματα 11 - 15 από τα 100.
Σελίδα 46
Produce AD both ways to the points G , H , and through B draw BG parallel ( 31. 1. ) to CA , and through F draw FH parallel to ED : Then each of the figures G D GBCA , DEFH is a paralH. lelogram ; and they are equal to ( 36. 1. ) ...
Produce AD both ways to the points G , H , and through B draw BG parallel ( 31. 1. ) to CA , and through F draw FH parallel to ED : Then each of the figures G D GBCA , DEFH is a paralH. lelogram ; and they are equal to ( 36. 1. ) ...
Σελίδα 54
From the point B draw ( 11. 1. ) BF at right angles to BC , and make BG equal ( 3. 1. ) to A ; and B D E C through G draw ( 31. 1. ) GH parallel to BC ; and through D , E , C , draw ( 31. 1. ) DK , EL , CH parallel to BG ; then BH ...
From the point B draw ( 11. 1. ) BF at right angles to BC , and make BG equal ( 3. 1. ) to A ; and B D E C through G draw ( 31. 1. ) GH parallel to BC ; and through D , E , C , draw ( 31. 1. ) DK , EL , CH parallel to BG ; then BH ...
Σελίδα 55
the А. C B square CDEB , and produce ED to F , and through A draw ( 31. 1. ) AF parallel to CD or BE ; then AE - AD + CE . But AE = AB.BE = AB.BC , because BE BC . So also AD AC.CD = AC.CB ; and CE = BC2 ; therefore AB.BC = AC.CB + BC .
the А. C B square CDEB , and produce ED to F , and through A draw ( 31. 1. ) AF parallel to CD or BE ; then AE - AD + CE . But AE = AB.BE = AB.BC , because BE BC . So also AD AC.CD = AC.CB ; and CE = BC2 ; therefore AB.BC = AC.CB + BC .
Σελίδα 56
DHG parallel to CE or BF ; and through H draw KLM parallel to CB or EF ; and ' С D B also through A draw AK parallel to CL or BM : And because CH = HF , if DM be added to both , KY M CM = DF . But AL = ( 36.1 . ) ...
DHG parallel to CE or BF ; and through H draw KLM parallel to CB or EF ; and ' С D B also through A draw AK parallel to CL or BM : And because CH = HF , if DM be added to both , KY M CM = DF . But AL = ( 36.1 . ) ...
Σελίδα 57
the square CEFD , join DE , and through B draw ( 31. 1 ) BHG parallel to CE or DF , and through H draw KLM parallel to AD or EF , and also through A draw AK parallel to CL or DM . And because AC is equal to CB , the rectangle ALis equal ...
the square CEFD , join DE , and through B draw ( 31. 1 ) BHG parallel to CE or DF , and through H draw KLM parallel to AD or EF , and also through A draw AK parallel to CL or DM . And because AC is equal to CB , the rectangle ALis equal ...
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ABC is equal ABCD altitude angle ABC angle BAC arch base bisected Book called centre circle circle ABC circumference coincide common cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular Euclid exterior angle extremity fall fore four fourth given given straight line greater half inscribed interior join less Let ABC magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism produced PROP proportionals proposition proved radius ratio reason rectangle contained rectilineal figure right angles segment shewn sides similar sine solid square straight line taken tangent THEOR thing third touches triangle ABC wherefore whole
Πληροφορίες βιβλιογραφίας
| Τίτλος | Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
| Συγγραφέας | John Playfair |
| Εκδότης | E. Duyckinck, and George Long, 1824 |
| Πρωτότυπο από | Πανεπιστήμιο της Ιντιάνα |
| Ψηφιοποιήθηκε στις | 15 Ιαν. 2009 |
| Μέγεθος | 333 σελίδες |
| Εξαγωγή αναφοράς | BiBTeX EndNote RefMan |