Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
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Αποτελέσματα 11 - 15 από τα 65.
Σελίδα 47
Equal triangles on the same side of bases , which are equal and in the same straight line , are between the same ... PROB , To describe a parallelogram that shall be equal to a given triangle , and have one of its angles equal to a ...
Equal triangles on the same side of bases , which are equal and in the same straight line , are between the same ... PROB , To describe a parallelogram that shall be equal to a given triangle , and have one of its angles equal to a ...
Σελίδα 48
TE It is required to describe a parallelogram that shall be equal to the given triangle ABC , and have one of its angles equal to D. Bisect ( 10. 1. ) BC in E , join AE , and at the point E in the straight line EC make ( 23 1. ) ...
TE It is required to describe a parallelogram that shall be equal to the given triangle ABC , and have one of its angles equal to D. Bisect ( 10. 1. ) BC in E , join AE , and at the point E in the straight line EC make ( 23 1. ) ...
Σελίδα 49
To a given straight line to apply a parallelogram , which shall be equal to a given triangle , and have one of its angles equal to a given rectilineal angle . Let AB be the given straight line , and C the given triangle , and D the ...
To a given straight line to apply a parallelogram , which shall be equal to a given triangle , and have one of its angles equal to a given rectilineal angle . Let AB be the given straight line , and C the given triangle , and D the ...
Σελίδα 50
And because the straight line HG meets the parallels KM , FG , the alternate angles MHG , HGF are equal ( 29. 1. ) ... From this it is manifest how to a given straight line to apply a parallelogram , which shall have an angle equal to a ...
And because the straight line HG meets the parallels KM , FG , the alternate angles MHG , HGF are equal ( 29. 1. ) ... From this it is manifest how to a given straight line to apply a parallelogram , which shall have an angle equal to a ...
Σελίδα 51
to DE and AD to BE : but BA is equal to AD ; C therefore the four straight lines BA , AD , DE , EB are equal to one another ... it is therefore a square , and it is described upon the given straight line AB : Which was to be done .
to DE and AD to BE : but BA is equal to AD ; C therefore the four straight lines BA , AD , DE , EB are equal to one another ... it is therefore a square , and it is described upon the given straight line AB : Which was to be done .
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ABC is equal ABCD altitude angle ABC angle BAC arch base bisected Book called centre circle circle ABC circumference coincide common cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular Euclid exterior angle extremity fall fore four fourth given given straight line greater half inscribed interior join less Let ABC magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism produced PROP proportionals proposition proved radius ratio reason rectangle contained rectilineal figure right angles segment shewn sides similar sine solid square straight line taken tangent THEOR thing third touches triangle ABC wherefore whole