The first and second books of Euclid explained to beginners, by C.P. Mason |
Αναζήτηση στο βιβλίο
Αποτελέσματα 6 - 10 από τα 21.
Σελίδα 148
... half the line ( CB ) , is equal to the on CD , which is the line made up of the half CB and the produced part BD , The steps of the preceding proof are exhibited in the following equations : - 1. Rect . A L = = rect . C H. 2. Rect . CH ...
... half the line ( CB ) , is equal to the on CD , which is the line made up of the half CB and the produced part BD , The steps of the preceding proof are exhibited in the following equations : - 1. Rect . A L = = rect . C H. 2. Rect . CH ...
Σελίδα 149
... half the line and the on the distance of the point of section from the middle of the line . In the fifth proposition the former of these two ☐s is the larger , in the sixth , the latter . PROPOSITION VII . If a straight line be divided ...
... half the line and the on the distance of the point of section from the middle of the line . In the fifth proposition the former of these two ☐s is the larger , in the sixth , the latter . PROPOSITION VII . If a straight line be divided ...
Σελίδα 152
... half the line together with twice the square on the line between the points of section . In the construction employed in this proposition we must be able , — 1. To join two given points by a straight line . ( Post . I. ) 2. From the ...
... half the line together with twice the square on the line between the points of section . In the construction employed in this proposition we must be able , — 1. To join two given points by a straight line . ( Post . I. ) 2. From the ...
Σελίδα 153
... half a right . In a similar way it may be shown that CEB is half a right . It follows , therefore , that A E B ( that is , AEF ) is a right < . 2. To prove that ADF is a right △ : EXPLAINED TO BEGINNERS . 153.
... half a right . In a similar way it may be shown that CEB is half a right . It follows , therefore , that A E B ( that is , AEF ) is a right < . 2. To prove that ADF is a right △ : EXPLAINED TO BEGINNERS . 153.
Σελίδα 154
... half a right ; consequently , the GFE is half a right < , and is equal to the It follows , therefore ( I. 4. To prove that DF is The threes of the GEF . 6 ) , that GE is equal to GF . equal to DB : - * - ECB are together equal to two ...
... half a right ; consequently , the GFE is half a right < , and is equal to the It follows , therefore ( I. 4. To prove that DF is The threes of the GEF . 6 ) , that GE is equal to GF . equal to DB : - * - ECB are together equal to two ...
Άλλες εκδόσεις - Προβολή όλων
The First and Second Books of Euclid Explained to Beginners, by C.P. Mason Euclides Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
A B and CD A B is equal AC and CB Æneid axiom beginner bisected centre Consequently diagonal draw a straight Edition equal in area equal respectively equal to twice equilateral Euclid exterior exterior angle Fcap figure finite right line follows formed fourth proposition given finite right given line given point given rectilineal given straight line gnomon Grammar greater half a right hypotenuse interior and opposite isosceles Join the points join two given Latin length less line A B line CB linear units lines are parallel magnitudes meeting the line opposite sides parallelogram point F proof Prop proposition prove this proposition rectangle contained right angles side A C straight line meets suppose three sides triangle unequal