Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
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Σελίδα 40
For , if not , KL and CD are either parallel , or they meet on the other side of EF ; but they are not parallel ; for the angles KGH , GHC would then be equal to two right angles . Neither do they meet on the other side of EF ; for the ...
For , if not , KL and CD are either parallel , or they meet on the other side of EF ; but they are not parallel ; for the angles KGH , GHC would then be equal to two right angles . Neither do they meet on the other side of EF ; for the ...
Σελίδα 41
to the straight line AB ; and because E AB is parallel to CE and AC meets them , the alternate angles BAC , ACE are equal ( 29 . 1. ) Again , because AB is B D F . > parallel to CE , and BD falls upon them OF GEOMETRY . 41 BOOK I.
to the straight line AB ; and because E AB is parallel to CE and AC meets them , the alternate angles BAC , ACE are equal ( 29 . 1. ) Again , because AB is B D F . > parallel to CE , and BD falls upon them OF GEOMETRY . 41 BOOK I.
Σελίδα 43
Join BC ; and because AB is pa- А. B rallel to CD , and BC meets them , the alternate angles ABC , BCD are equal ( 29. 1. ) ; and because AB is equal to CD , and BC common to the two triangles ABC , DCB , the two sides AB , BC are equal ...
Join BC ; and because AB is pa- А. B rallel to CD , and BC meets them , the alternate angles ABC , BCD are equal ( 29. 1. ) ; and because AB is equal to CD , and BC common to the two triangles ABC , DCB , the two sides AB , BC are equal ...
Σελίδα 49
Therefore HB , FE will meet , if produced ; let them meet in K , and l througb K draw KL parallel to EA or FH , and produce HA , GB to the points L , M : Then HLKF is a parallelogram , of which the diameter is HK , and AG , ME are the ...
Therefore HB , FE will meet , if produced ; let them meet in K , and l througb K draw KL parallel to EA or FH , and produce HA , GB to the points L , M : Then HLKF is a parallelogram , of which the diameter is HK , and AG , ME are the ...
Σελίδα 50
... HG meets the parallels KM , FG , the alternate angles MHG , HGF are equal ( 29. 1. ) ; add to each of these the angle HGL ; therefore the angles MHG . HGL , are equal o the angles HGF , HGL : But the angles MHG , HGL , are equal ...
... HG meets the parallels KM , FG , the alternate angles MHG , HGF are equal ( 29. 1. ) ; add to each of these the angle HGL ; therefore the angles MHG . HGL , are equal o the angles HGF , HGL : But the angles MHG , HGL , are equal ...
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ABC is equal ABCD altitude angle ABC angle BAC arch base bisected Book called centre circle circle ABC circumference coincide common cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular Euclid exterior angle extremity fall fore four fourth given given straight line greater half inscribed interior join less Let ABC magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism produced PROP proportionals proposition proved radius ratio reason rectangle contained rectilineal figure right angles segment shewn sides similar sine solid square straight line taken tangent THEOR thing third touches triangle ABC wherefore whole