The North American Arithmetic: Part Third, for Advanced Scholars, Τόμος 3Russell, Odiorne, & Metcalf, 1834 - 288 σελίδες |
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Σελίδα 84
... months . How many men must leave the garrison , that the provision may last the remainder 9 months ? 138. If a loaf of bread weighing 32 ounces be sold for eight cents , when flour is worth $ 6.50 per barrel , what ought the eight ...
... months . How many men must leave the garrison , that the provision may last the remainder 9 months ? 138. If a loaf of bread weighing 32 ounces be sold for eight cents , when flour is worth $ 6.50 per barrel , what ought the eight ...
Σελίδα 85
... months ? 141. How many tiles 8 inches square , will cover a hearth 16 feet long , and 12 feet wide ? 142. If the ... months . At the end of 3 months she captured an enemy's vessel , and put 75 men on board of her . Five months after ...
... months ? 141. How many tiles 8 inches square , will cover a hearth 16 feet long , and 12 feet wide ? 142. If the ... months . At the end of 3 months she captured an enemy's vessel , and put 75 men on board of her . Five months after ...
Σελίδα 93
... per cent . or .18 , and so on . The interest of 24 dollars for 3 years , at 6 per cent . a year , is found thus , 24 X.18 = $ 4.32 , the interest sought . RATE PER CENT . FOR MONTHS . The decimal ex- XV . 93 INTEREST . Interest.
... per cent . or .18 , and so on . The interest of 24 dollars for 3 years , at 6 per cent . a year , is found thus , 24 X.18 = $ 4.32 , the interest sought . RATE PER CENT . FOR MONTHS . The decimal ex- XV . 93 INTEREST . Interest.
Σελίδα 94
... months , when the rate is 6 per cent . a year , is easily obtained ; for , if the rate for 12 months be 6 per cent . or .06 , for 1 month it is of 6 per cent . which is per cent . or .005 ; for 2 months it is 1 per cent . or .01 ; for 3 ...
... months , when the rate is 6 per cent . a year , is easily obtained ; for , if the rate for 12 months be 6 per cent . or .06 , for 1 month it is of 6 per cent . which is per cent . or .005 ; for 2 months it is 1 per cent . or .01 ; for 3 ...
Σελίδα 95
... months , we multiply the rate for 1 month by 7 ; thus , .005 X 7 = .035 . To find the rate for 19 days , we denote ... months , at 6 per cent . a year ? 10. What will 713 dollars 33 cents amount to , in 2 years and 10 months , at 6 per ...
... months , we multiply the rate for 1 month by 7 ; thus , .005 X 7 = .035 . To find the rate for 19 days , we denote ... months , at 6 per cent . a year ? 10. What will 713 dollars 33 cents amount to , in 2 years and 10 months , at 6 per ...
Άλλες εκδόσεις - Προβολή όλων
The North American Arithmetic: part third, for advanced scholars Frederick Emerson Πλήρης προβολή - 1851 |
The North American Arithmetic: Part Third, for Advanced Scholars Frederick Emerson Πλήρης προβολή - 1834 |
Συχνά εμφανιζόμενοι όροι και φράσεις
75 cents acres annuity annum avoirdupois bajocchi Bill breadth bushels called carats cask ciphers compound interest contain continual proportionals cost cube root denominator denoted diameter discount divided dividend divisor dollars 50 cents dry measure Ducat equal example exchange expressed Extract the square factors Federal money feet long figure Find a mean Flemish florin foot francs frustrum gallons given number Hamburgh hogshead hundred improper fraction least common multiple length London maravedis mean proportional measure merchant miles minuend mixed number months multiplied number of terms number of things ounces paid payable payment pence pezza places pound sterling pounds present worth quantity quotient ratio received Reduce remainder repetend rix dollar rods RULE rupee scudo series of continual shillings sold Spanish dollars square root sterling Subtract Suppose third power United vulgar fraction weight whole number wide wine yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 114 - Multiply each debt by its term of credit, and divide the sum of the products by the sum of the debts. The quotient will be the average term of credit.
Σελίδα 178 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 7 - ... 11 eleven 12 twelve 13 thirteen 14 fourteen 15 fifteen 16 sixteen 17 seventeen 18 eighteen 19 nineteen 20 twenty 21 twenty-one...
Σελίδα 183 - Bring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor as before, and in like manner proceed till the whole be finished.
Σελίδα 265 - ... last product by 95, the quotient whereof shall be deemed the true contents or tonnage of such ship or vessel; and if such ship or vessel be single-decked, take the length and breadth, as above directed, deduct from...
Σελίδα 184 - ... 5, 7, 9, 11, 13, 15, &c. is an ascending series. ( 15, 13, 11, 9, 7, 5, 3, &c. is a descending series. The numbers which form the series are called the terms of the series. The first and last terms are the extremes, and the other terms are called the means. There are five things in arithmetical progression, any three of which being given, the other two may be found : — 1st.
Σελίδα 7 - Cardinal numbers: 1 one 2 two 3 three 4 four 5 five 6 six 7 seven 8 eight 9 nine 10 ten 11 eleven 12 twelve 13 thirteen 14 fourteen 15 fifteen 16 sixteen 17 seventeen 18 eighteen 19 nineteen 20...
Σελίδα 171 - ... is equal to the square root of the difference of the squares of the hypotenuse and the other leg.
Σελίδα 177 - Find how many times the divisor is contained in the dividend, and place the result in the quotient.
Σελίδα 178 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend...