Stewart's specific subjects. Euclid. [1st] (-3rd stage). [With 2 issues of] Algebra |
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Αποτελέσματα 6 - 10 από τα 21.
Σελίδα 20
... parallelogram BEFG equal to C , having EBG equal to D , so that BE be in the same straight line with AB ; produce FG ... parallelogram ; the diameter is HK ; and AG , ME , are the parallelograms about HK ; and LB , BF , the complements ...
... parallelogram BEFG equal to C , having EBG equal to D , so that BE be in the same straight line with AB ; produce FG ... parallelogram ; the diameter is HK ; and AG , ME , are the parallelograms about HK ; and LB , BF , the complements ...
Σελίδα 21
... parallelogram ; and because the triangle ABD is equal to HF , and DBC to GM , the whole ABCD is equal to the whole KFLM ; therefore KFLM has been made equal to ABCD , having FKM equal to the given angle E. XLVI . - To describe a square ...
... parallelogram ; and because the triangle ABD is equal to HF , and DBC to GM , the whole ABCD is equal to the whole KFLM ; therefore KFLM has been made equal to ABCD , having FKM equal to the given angle E. XLVI . - To describe a square ...
Σελίδα 25
... parallelogram , of which BC is a diameter . Because AB is parallel to CD , and BC meets them , the alternate angles ... parallelograms are equal to one another ; also , their diameter bisects them ; for AB being equal to CD , and BC ...
... parallelogram , of which BC is a diameter . Because AB is parallel to CD , and BC meets them , the alternate angles ... parallelograms are equal to one another ; also , their diameter bisects them ; for AB being equal to CD , and BC ...
Σελίδα 26
... parallelograms ABCD , EBCF , be upon the same base BC , and between the same parallels AF , BC . If the sides AD , DF , of the parallelograms ABCD , DBCF ... parallelogram EFGH is equal to the same EBCH ; therefore , also 26 GEOMETRY .
... parallelograms ABCD , EBCF , be upon the same base BC , and between the same parallels AF , BC . If the sides AD , DF , of the parallelograms ABCD , DBCF ... parallelogram EFGH is equal to the same EBCH ; therefore , also 26 GEOMETRY .
Σελίδα 27
... parallelogram ; and EBCA is equal to DBCF , because they are upon the same base BC , and between the same parallels BC , EF ; and the triangle ABC is the half of the parallelogram EBCA , because the diameter AB bisects it ; and DBC is ...
... parallelogram ; and EBCA is equal to DBCF , because they are upon the same base BC , and between the same parallels BC , EF ; and the triangle ABC is the half of the parallelogram EBCA , because the diameter AB bisects it ; and DBC is ...
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Stewart's Specific Subjects. Euclid. [1st] (-3rd Stage). [With 2 Issues Of ... Stewart W and Co Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
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Δημοφιλή αποσπάσματα
Σελίδα 19 - If two triangles have two sides of the one equal to two sides of the...
Σελίδα 1 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a Right Angle; and the straight line which stands on the other is called a Perpendicular to it.
Σελίδα 8 - Upon the same base, and on the same side of it, there cannot be two triangles, that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity, equal to one another.
Σελίδα 16 - Any two sides of a triangle are together greater than the third side.
Σελίδα 12 - IF a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Σελίδα 5 - IF two angles of a triangle be equal to one another, the sides also which subtend, or are opposite to, the equal angles, shall be equal to one another.