An Introduction to Algebra Upon the Inductive Method of InstructionCummings, Hilliard, 1826 - 276 σελίδες |
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Αποτελέσματα 6 - 10 από τα 37.
Σελίδα 98
... quotient will be the multiplicand . Again , the three terms 4 abc - 6 a3 b3 c2 + 2 a2 b * c c3 of the product were formed by multiplying each term of the multiplicand by 2 a b c . Therefore , if these three terms be di- vided by 2 ab c ...
... quotient will be the multiplicand . Again , the three terms 4 abc - 6 a3 b3 c2 + 2 a2 b * c c3 of the product were formed by multiplying each term of the multiplicand by 2 a b c . Therefore , if these three terms be di- vided by 2 ab c ...
Σελίδα 99
... quotient could be ascer- tained . This cannot often be done by inspection ; for in many products , though at first there are as many terms as there are in the multiplicand and multiplier together , some of the terms are united together ...
... quotient could be ascer- tained . This cannot often be done by inspection ; for in many products , though at first there are as many terms as there are in the multiplicand and multiplier together , some of the terms are united together ...
Σελίδα 100
... quotient , but which was formed by multiplying each remaining term of the quotient by all the terms of the divisor . This then is a new dividend , and to find the next term of the quotient we must proceed exactly as before ; that is ...
... quotient , but which was formed by multiplying each remaining term of the quotient by all the terms of the divisor . This then is a new dividend , and to find the next term of the quotient we must proceed exactly as before ; that is ...
Σελίδα 101
... quotient must be + b , be- ax + b gives a b . cause - The rule for signs therefore is the same as in multiplication ... quotient must be ― By the reasoning above we derive the following rule for di- vision of compound numbers . Arrange ...
... quotient must be + b , be- ax + b gives a b . cause - The rule for signs therefore is the same as in multiplication ... quotient must be ― By the reasoning above we derive the following rule for di- vision of compound numbers . Arrange ...
Σελίδα 102
... quotient . - Examples . x2 1. Divide + 2 a x + a2 by a + x . * 2. Divide a2 - b3 by a + b . 3. Divide b * + 2 b2 x + x2 by b2 + x . 4. Divide 203 3 y3 by x2 + xy + y2 . 5. Divide X3 3 — y3 by x + y . 6. Divide 15 a2 + 2ab - 8b2 by 3a ...
... quotient . - Examples . x2 1. Divide + 2 a x + a2 by a + x . * 2. Divide a2 - b3 by a + b . 3. Divide b * + 2 b2 x + x2 by b2 + x . 4. Divide 203 3 y3 by x2 + xy + y2 . 5. Divide X3 3 — y3 by x + y . 6. Divide 15 a2 + 2ab - 8b2 by 3a ...
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Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra: Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1837 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
An Introduction to Algebra upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1844 |
Συχνά εμφανιζόμενοι όροι και φράσεις
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