Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids : to which are Added, Elements of Plane and Spherical TrigonometryMarot & Walter, 1826 - 320 σελίδες |
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Αποτελέσματα 6 - 10 από τα 80.
Σελίδα 41
... reason , the parallelogram EFGH is equal to the same EBCH : Therefore also the parallelo- gram ABCD is equal to EFGH . Wherefore , parallelograms , & c . Q. E. D. PROP . XXXVII . THEOR . Triangles upon the same base , and between the ...
... reason , the parallelogram EFGH is equal to the same EBCH : Therefore also the parallelo- gram ABCD is equal to EFGH . Wherefore , parallelograms , & c . Q. E. D. PROP . XXXVII . THEOR . Triangles upon the same base , and between the ...
Σελίδα 44
... reason , the triangle KGC is equal to the triangle KFC . Then , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to the triangle KFC ; the triangle AEK , together with the triangle KGC is equal to the ...
... reason , the triangle KGC is equal to the triangle KFC . Then , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to the triangle KFC ; the triangle AEK , together with the triangle KGC is equal to the ...
Σελίδα 47
... reason , AB and AH are in the same straight line , Now because the angle DBC is equal to the angle FBA , each of them being a right angle , adding to each the angle ABC , the whole augie DBA will be equal ( 2. Ax . ) to the whole FBC ...
... reason , AB and AH are in the same straight line , Now because the angle DBC is equal to the angle FBA , each of them being a right angle , adding to each the angle ABC , the whole augie DBA will be equal ( 2. Ax . ) to the whole FBC ...
Σελίδα 51
... reason HF also is a square , and it is upon the side HG , which is equal to AC ; therefore HF , CK are the squares of AC , CB . And because the complement AG is equal ( 43. 1. ) to the complement GE ; and because AGAC.CGAC.CB ...
... reason HF also is a square , and it is upon the side HG , which is equal to AC ; therefore HF , CK are the squares of AC , CB . And because the complement AG is equal ( 43. 1. ) to the complement GE ; and because AGAC.CGAC.CB ...
Σελίδα 54
... reason , PR is equal to RO ; and because CB is equal to BD , and GK to KN , the rectangles CK and BN are equal , as also the rectangles GR and RN : But CK is equal ( 43. 1. ) to RN , because they are the complements of the parallelogram ...
... reason , PR is equal to RO ; and because CB is equal to BD , and GK to KN , the rectangles CK and BN are equal , as also the rectangles GR and RN : But CK is equal ( 43. 1. ) to RN , because they are the complements of the parallelogram ...
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Elements of Geometry: Containing the First Six Books of Euclid; With Two ... Formerly Chairman Department of Immunology John Playfair Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angle EDF arch AC base BC bisected centre circle ABC circumference cosine cylinder demonstrated diameter draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater hypotenuse inscribed join less Let ABC Let the straight line BC meet multiple opposite angle parallel parallelogram perpendicular polygon prism PROB produced proportionals proposition Q. E. D. COR Q. E. D. PROP radius ratio rectangle contained rectilineal figure remaining angle segment semicircle side BC sine solid angle solid parallelopipeds spherical angle spherical triangle straight line AC THEOR third touches the circle triangle ABC triangle DEF wherefore
Δημοφιλή αποσπάσματα
Σελίδα 125 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 39 - THE straight lines which join the extremities of two equal and parallel straight lines, towards the same parts, are also themselves equal and parallel. Let AB, CD be equal and parallel straight lines, and joined towards the same parts by the straight lines AC, BD ; AC, BD are also equal and parallel.
Σελίδα 41 - Parallelograms upon the same base and between the same parallels, are equal to one another.
Σελίδα 19 - BG; and things that are equal to the same are equal to one another; therefore the straight line AL is equal to BC. Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC.
Σελίδα 145 - If two triangles which have two sides of the one proportional to two sides of the other, be joined at one angle, so as to have their homologous sides parallel to one another ; the remaining sides shall be in a straight line. Let ABC, DCE be two triangles which have the two sides BA, AC proportional to the two CD, DE, viz.
Σελίδα 30 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle.
Σελίδα 136 - FGL, have an angle in one equal to an angle in the other, and their sides about these equal angles proportionals ; the triangle ABE is equiangular (6.
Σελίδα 51 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Σελίδα 20 - DEF, and be equal to it ; and the other angles of the one shall coincide with the remaining angles of the other and be equal to them, viz. the angle ABC to the angle DEF, and the angle ACB to DFE.
Σελίδα 55 - If a straight line be divided into two equal, and also into two unequal parts ; the squares on the two unequal parts are together double of the square on half the line, and of the square on the line between the points of section.