Conversations on Arithmetic, with Demonstrations to Each RuleLincoln & Edmands, 1823 - 156 σελίδες |
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Αποτελέσματα 6 - 10 από τα 25.
Σελίδα 17
... stand after 1823 , to make anoth- er number of years just equal to the number from the creation to the Christian era ? Ans . 2181 years . CONVERSATION II . SIMPLE MULTIPLICATION AND SIMPLE DIVISION . Tut . Can you tell what simple ...
... stand after 1823 , to make anoth- er number of years just equal to the number from the creation to the Christian era ? Ans . 2181 years . CONVERSATION II . SIMPLE MULTIPLICATION AND SIMPLE DIVISION . Tut . Can you tell what simple ...
Σελίδα 19
... stand under units , tens under tens , & c . and draw a line beneath . Begin with the unit figure of the multiplier , and multiply each figure of the multiplicand by it , setting the excess of tens in the product of the two figures ...
... stand under units , tens under tens , & c . and draw a line beneath . Begin with the unit figure of the multiplier , and multiply each figure of the multiplicand by it , setting the excess of tens in the product of the two figures ...
Σελίδα 21
... stand it thoroughly before you proceed further . Pup . Does it never happen that the multiplier is larg . er than the multiplicand ? Tut . This never happens , because either of the num- bers may be used for a multiplier , and the ...
... stand it thoroughly before you proceed further . Pup . Does it never happen that the multiplier is larg . er than the multiplicand ? Tut . This never happens , because either of the num- bers may be used for a multiplier , and the ...
Σελίδα 24
... stand thus : - dividend . divisor , 16 ) 2 4 8 1 5 quotient . 16 8 8 8 0 8 remainder . Pup . The work here is plain , but I do not understand the reason of multiplying the divisor by the quotient fig- ure , and subtracting as I do . I ...
... stand thus : - dividend . divisor , 16 ) 2 4 8 1 5 quotient . 16 8 8 8 0 8 remainder . Pup . The work here is plain , but I do not understand the reason of multiplying the divisor by the quotient fig- ure , and subtracting as I do . I ...
Σελίδα 25
... stand thus : - 2 4 ) 6 4 2 6 8 ( 4. Here you are in the first place to find how often 24 is contained in 64 ; 64 here is not merely 64 , but 64,000 ; therefore we will suppose the dividend to be 64,000 , and divide it by 24 . 2 4 ) 6 4 ...
... stand thus : - 2 4 ) 6 4 2 6 8 ( 4. Here you are in the first place to find how often 24 is contained in 64 ; 64 here is not merely 64 , but 64,000 ; therefore we will suppose the dividend to be 64,000 , and divide it by 24 . 2 4 ) 6 4 ...
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Conversations on Arithmetic, with Demonstrations to Each Rule Leonard Pierce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Conversations on Arithmetic, with Demonstrations to Each Rule Leonard Pierce Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
addition alligation annexed answer arithmetic blocks borrowed called carats cents and mills cents per bushel ciphers circumference compound interest compound number contained cost cube root currencies to Federal debt decimal fractions diameter difference dimes discount divide dividend division dollars double Duodecimals equal Examples for Practice expressed Federal Money feet find the price following numbers following rule gain gallons give given number grains greatest common divisor Hence higher denomination hundred weight improper fraction inches last quotient figure left hand period lower denomination manner miles minuend mixed number months multiplicand number of tens ounces payment pennyweights perform place of tens pound present worth proceed proportion quantity reduce remainder required to multiply right hand figure share simple number square root subtrahend supposed number tenths tion triple quotient TROY WEIGHT understand units vulgar fractions whole numbers write
Δημοφιλή αποσπάσματα
Σελίδα 153 - EF or his certain attorney, his executors, administrators or assigns, to which payment, well and truly to be made, I bind myself, my heirs, executors and administrators, firmly by these presents ; Sealed with my seal.
Σελίδα 37 - To change a mixed number to an improper fraction, multiply the whole number by the denominator of the fraction and add the numerator.
Σελίδα 118 - RULE.—Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time.* • , EXAMPLES.
Σελίδα 126 - Distinguish the given number into periods of two figures each, by putting a point over the place of units, another 'over the place of hundreds, and so on, which points show the number of figures the root will consist of. 2. Find the greatest square number in the first or left hand period...
Σελίδα 155 - SP his heirs, and assigns, a certain tract and parcel of land, bounded as follows, viz. [Here insert the bounds, together with all the privileges and appurtenances thereunto belonging.'} To have and to hold the same unto the said SP his heirs and assigns, to his and their use and behoof for ever.
Σελίδα 109 - If 248 men, in 5 days, of 11 hours each, can dig a trench 230 yards long, 3 wide, and 2 deep, in how many days, of 9 hours each, will 24 men dig a trench 420 yards long, 5 wide, and 3 deep ? Here the number of days, in which the proposed work can be done, depends on five circumstances, viz.
Σελίδα 127 - Double the figures already found in the root for a new divisor, (or, bring down your last divisor for a new one, doubling the right hand figure of it,) and from these find the next figure in the root, as last directed, and continue the operation in the same manner, till you have brought down all the periods.
Σελίδα 131 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 156 - Lord eighteen hundred and , with lawful interest for the same until paid, then this deed, as also a certain bond [or note, as the case may be] bearing even date with these presents given by me to the said RS conditioned t...
Σελίδα 107 - A and B depart from the same, place and travel the same road ; but A goes 5 days before B, at the rate of 15 miles a day . B follows at the rate of 20 miles a . day } what distance must he travel to overtake A ? Ans. 300 miles RULE OF THREE INVERSE.