| Fletcher Durell - 1904 - 382 σελίδες
...area of a rectangle 8 yds. long and 5 ft. wide. BOOK IV. PLANE GEOMETRY PROPOSITION IV. THEOREM 385. The area of a parallelogram is equal to the product of its base by its altitude. KB FC Given the ZZ7 ABCD with the base AD (denoted by 6) and the altitude DF... | |
| Fletcher Durell - 1911 - 553 σελίδες
...Find, in square feet, the area of a rectangle 8 yds. long and 5 ft. wide. PROPOSITION IV. THEOREM 385. The area of a parallelogram is. equal to the product of its base by its altitude. K__B__ pa A b D Given the ZZ7 ABCD with the base AD (denoted by b) and the altitude... | |
| Fletcher Durell - 1904 - 232 σελίδες
...side. BOOK IV. 383. The area of a rectangle is equal to the product of its base by its altitude. 385. The area of a parallelogram is equal to the product of its base by its altitude. 389. The area of a triangle is equal to one-half the product of its base by its... | |
| George Albert Wentworth - 1904 - 496 σελίδες
...evident by dividing the figure into squares, each BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. CF CE A b DA b D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
| George Clinton Shutts - 1905 - 260 σελίδες
...fractional number of times in the base and altitude the same rule is reached. PROPOSITION IV. 330. Theorem. The area of a parallelogram is equal to the product of its base and altitude. Suggestion. § 323 and § 326. PROPOSITION V. 331. Theorem. The area of a triangle is equal to one-half... | |
| Elmer Adelbert Lyman - 1905 - 268 σελίδες
...C'fi, thus forming a rectangle with the, same base and altitude as the given parallelogram. Therefore,^ the area of a parallelogram is equal to the product of its base and altitude, or A = ab. 188. The Triangle. Since the line AB divides the parallelogram into two equal triangles... | |
| George Albert Wentworth, David Eugene Smith - 1913 - 496 σελίδες
...wide a road is cut 4 rd. wide. How many acres are cut off for the road? PROPOSITION IV. THEOREM 322. The area of a parallelogram is equal to the product of its base by its altitude. A b BA b B Given the parallelogram ABCD, with base b and altitude a. To prove... | |
| Walter Burton Ford, Charles Ammerman - 1913 - 184 σελίδες
...their bases; two rectangles that have equal bases are to each other as their altitudes. 186. Theorem I. The area of a parallelogram is equal to the product of its base by its altitude. 187. Corollary 1. (a) Two parallelograms are to each other as the products of... | |
| George E. Mercer, Mabel Bonsall - 1914 - 324 σελίδες
...should be given practice in drawing them until the mention of a name calls forth an appropriate drawing. The area of a parallelogram is equal to the product of its base and altitude. The base and altitude must be expressed in units of the same kind. The diagonal of a parallelogram... | |
| William James Milne - 1914 - 524 σελίδες
...resulting figure will be a rectangle of the same area, base, and altitude as the BASE parallelogram. The area of a parallelogram is equal to the product of its base and altitude, expressed in like units. ' ' " and Written Exercises Estimate results mentally before solving. Find... | |
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