 | Isaac Todhunter - 1880 - 426 σελίδες
...right angles as the figure has sides. But, by the foregoing Corollary all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Therefore all the interior angles of the figure, together with all its exterior angles, are... | |
 | Oxford univ, local exams - 1880 - 396 σελίδες
...a circle, and by a straight line placed in a circle. 2. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 3. If the square described on one side of a triangle be equal to the squares described on the... | |
 | Sir Norman Lockyer - 1880 - 668 σελίδες
...the flat angle we may take Theorem XXVI. of the syllabus, that the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. In the new notation we would say that the sum of the interior angles of the polygon is equal... | |
 | Elias Loomis - 1880 - 452 σελίδες
...is the complement of the other. PROPOSITION XXVIII. THEOREM. All the interior angles of a polygon, together with four right angles, are equal to twice as many right angles as the figure IMS sides. Let ABCDE be any polygon ; then all its interior angles A, B, C, D, E, together with four... | |
 | Thomas Holloway (surveyor.) - 1881 - 132 σελίδες
...four right angles or three hundred and sixty degrees. 3. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Although further systems of proof could easily be quoted, I consider the foregoing quite sufficient... | |
 | John Gibson - 1881 - 302 σελίδες
...greater side, or has the greater side opposite to it. 3. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 4. Describe a parallelogram that shall be equal to a given triangle BCD, and have one of its... | |
 | Thomas Newton Andrews - 1881 - 168 σελίδες
...— In Euclid, Book I., Prop, xxxi11., it is proved that "All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides." If we have to describe a pentagon on the base AB, we must first calculate the angles at the... | |
 | College of preceptors - 1882 - 528 σελίδες
...for the demonstration of which this one is referred to. 5. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 6. The opposite sides and angles of a parallelogram are equal ; and the diameter bisects the... | |
 | 1882 - 498 σελίδες
...also equal, the triangles must be equal in every respect. 4 All the interior angles of any rectilineal figure together with four right angles, are equal to twice as many right angles as the figure has sides. 5. Equal triangles upon equal bases in the same straight line and towards the same parts are... | |
 | 1882 - 486 σελίδες
...In corollaries to the same proposition it is shown that all the internal angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides ; also, that all the external angles of any rectilineal figure formed by producing the sides... | |
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Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
