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" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
Ruger's Arithmetick, with Questions and Answers: A New System of Arithmetick ... - Σελίδα 242
των William Ruger - 1841 - 263 σελίδες
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An Elementary Arithmetic Serving as an Introduction to the Higher Arithmetic

George Roberts Perkins - 1850 - 364 σελίδες
...Having written the three terms of the proportion, or, as usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by the first term. NOTE. — Since there is a ratio between the firsthand second terms, they must be reduced to...

The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - 1850 - 412 σελίδες
...least of the remaining numbers in the first place, but when it is less place the greater there. IV. Then multiply the second and third terms together, and divide the product by the ßrst term : the quotient will be the fourth term or answer sought, and will be of the same denomination...

Arithmetic on the Productive System: Accompanied by a Key and ..., Τόμος 1

Roswell Chamberlain Smith - 1850 - 314 σελίδες
...the means is 21,600, which, being divided by one of the extremes, gives a quotient of 720. That is, multiply the second and third terms together, and divide the product by the first ; the quotient will be the fourth term or answer. A. $720. 14. If 20 pounds of butter cost 85, what...

A New System of Arithmetic on an Improved Plan

Charles Guilford Burnham - 1850 - 350 σελίδες
...expresses the demand, for the first, and the remaining term of the condition for the second term. II. Multiply the second and third terms together, and divide the product by the first. III. If the first or second terms consist of different denominations, reduce both to the lowest mentioned....

The scholar's guide to arithmetic; or, A complete exercise-book

John Bonnycastle - 1851 - 314 σελίδες
...when necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ;...

The Western Practical Arithmetic ...: Containing a Great Variety of ...

1851 - 260 σελίδες
...of them till they are; and, if the third consist of several denominations, reduce it to the lowest, then Multiply the second and third terms together and divide the product by the FIRST, and the quotient will be the fourth term or answer. NOTE.— The answer will be of the same denomination...

The young ladies' guide to practical arithmetic and book-keeping, with forms ...

G. Morrison - 1851 - 130 σελίδες
...greater than the third, place the least of the other two terms as the first ; but it' less, the contrary. Multiply the second and third terms together, and divide the product by the first, and the quotient is the answer, and which is always of the same name with that to which the third term...

Encyclopædia Americana: A Popular Dictionary of Arts, Sciences ..., Τόμος 11

Francis Lieber, Edward Wigglesworth, Henry Vethake - 1851 - 624 σελίδες
...less, place the greater of these two terms on the left, and the less in the middle ; and in both cases, multiply the second and third terms together, and divide the product by the first term for the answer, which will always be of the same denomination as the third term. — Note 1. If...

An Epitome of Navigation and Nautical Astronomy, with Improved Lunar Tables ...

Janet Taylor - 1851 - 674 σελίδες
...the first and third terms may be of the same kind, and the second the same am the number required. Multiply the second and third terms together, and divide the product by the first term, then the quotient will be the answer in the same denomination as the second term, observing to...

Encyclopædia Americana: A Popular Dictionary of Arts, Sciences ..., Τόμος 11

Francis Lieber - 1851 - 618 σελίδες
...less, place the greater of these two terms on the left, and the less in the middle; and in both cases, multiply the second and third terms together, and divide the product by the first term for the answer, which will always be of the same denomination as the third term.—Note I. If...




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