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Βιβλία Βιβλία 71 - 80 από 151 για Then multiply the second and third terms together, and divide the product by the....
" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
Ruger's Arithmetick, with Questions and Answers: A New System of Arithmetick ... - Σελίδα 242
των William Ruger - 1841 - 263 σελίδες
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Watson's Tutor's assistant: or, Complete school arithmetic

William Watson (of Beverley.) - 1845
...Bring the first and third into one name, and the second into the lowest name mentioned in it. 3. — Multiply the second and third terms together and divide the product by the first, the quotient will be the answer to the question in the same name the second term was brought into....

North American Arithmetic: Part Second and Part Third, Μέρος 2

Frederick Emerson - 1846
...than the third, make the less of the two remaining terms the second term, and the greater the first. Multiply the second, and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. If there are different denominations in the...

An Elementary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1846 - 258 σελίδες
...Having written the three terms of the proportion, or, at usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by <A« first term. :!:NoTE. — Since there is a ratio between the first and cond terms, they must be...

The United States Arithmetic: Designed for Academies and Schools

William Vogdes - 1847 - 256 σελίδες
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. Multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination as the third term. 3. If either...

Welch's Improved American Arithmetic, Adapted to the Currency of the United ...

Oliver Welch - 1847 - 228 σελίδες
...denomination; and reduce the middle number, or term, into the lowest denomination mentioned; then (7) multiply the second and third terms together, and divide the product by the first; the quotient will be (°) the answer, or fourth term sought; and always will be (a) of the same denomination...

A familiar explanation of the higher parts of arithmetic

rev. Frederick Calder - 1848
...so : and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then multiply the second and third terms together, and divide the product by the first: the quotient will be the answer or fourth term, expressed in the same denomination as that in which...

An Arithmetical Dictionary: Or Book of Reference: Comprising a System of ...

William B. Young - 1848 - 297 σελίδες
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen multiply the second and third Terms together, and divide the product by the first Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term...

A Treatise on Mental Arithmetic, in theory and practice

Isaiah Steen - 1848
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, multiply the second and third terms together, and divide the product by the first term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination...

Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ...

Nathan Daboll, David Austin Daboll - 1849 - 249 σελίδες
...place the least of the two remaining numbers fqr the second term, and the greater for the first term ; then multiply' the second and third terms together, and divide the -product by the first term, and the quotient will be the answer in the same name "of the third term EXAMPLES. 1. If 6 yards...

Scribner's Engineers' and Mechanics' Companion: Comprising United States ...

J. M. Scribner - 1849 - 264 σελίδες
...of the two remaining numbers for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. NOTE. — If the first...




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