 | John Barter (of the science and art coll, Plymouth.) - 1877 - 328 σελίδες
...perpendicular B c = 4 ; required the hypothenuse, A B. 42 + 32 = 25, then ^25 = 5, the hypothenuse A B. 2. The square root of the difference of the squares of the hypothenuse and either side will give the other ; or, multiply the sum of the hypothenuse and either side by their... | |
 | Henry Bartlett Maglathlin - 1881 - 418 σελίδες
...root of the sum of the squares of the other two sides. 390. To find the base or perpendicular, Take the square root of the difference of the squares of the hypothenuse and the other side. 1. The base of a right-angled triangle is 8, and the perpendicular 6. What is the hypothenuse... | |
 | Henry H. Hutton - 1882 - 178 σελίδες
...squares of the hypothenuse and perpendicular; or, b= Vh 8 — p 8 . Rule VI. The perpendicular equals the square root of the difference of the squares of the hypothenuse and base; or p= v^h^-b 8 . EXERCISE IV. 1. In a right-angled triangle the base is 4 and the perpendicular... | |
 | Henry Bartlett Maglathlin - 1882 - 398 σελίδες
...root of the sum of the squares of the otlwr two sides. 390. To find the base or perpendicular, Take the square root of the difference of the squares of the hypothenuse and the other side. 1. The base of a right-angled triangle is 8, and the perpendicular 6. What is the hypotheuuse... | |
 | Charles Scott Venable - 1888 - 402 σελίδες
...square root of the sum of the squares of the two sides. II. A side of a right-angled triangle equals the square root of the difference of the squares of the hypothenuse and the other side. III. The circumference of a circle equals 3.1416- times the diameter ; or 6.2832- times... | |
 | Henry B. Maglathlin - 1894 - 370 σελίδες
...the other two sides; and 3. Either of the two shorter sides of a right-angled triangle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Exercises. 1. If the base of a right-angled triangle is 60 feet, and the perpendicular... | |
 | Alfred John Pearce - 1897 - 202 σελίδες
...hypothenuse and base are given. Now p2 + 62 = A2 .'. p2 = A2 - I2 = (ft + 6) (^ - 6) 6) (A - 6 RULE. — Take the square root of the difference of the squares of the hypothenuse and base ; or, Take the square root of the product of the sum and difference of the hypothenuse and base.... | |
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The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the... 
