 Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor' by the last remainder, till nothing remains, the last divisor is the common measure.* 2. Divide both of the...  Daboll's Schoolmaster's Assistant - Σελίδα 156των Nathan Daboll - 1828 - 247 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Zadock Thompson - 1832 - 182 σελίδες
...two numbers, RULE. — Divide the greater number by the less, and the divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remains ; then will the last divisor be the common divisor required. QUESTIONS FOR PRACTICE. 2. What is the... | |
 | Zadock Thompson - 1832 - 186 σελίδες
...two numbers. RULE. — Divide the greater number by the less, and the divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothmg remains ; then will the last divisor be the common divisor required. QUESTIONS FOR PRACTICE.... | |
 | Catharine Esther Beecher - 1833 - 296 σελίδες
...Divide the greater number by the less. Divide the divisor by the remainder, and continue to^divide the last divisor by the last remainder., till nothing remains. The last divisor is the greatest common measure, by which both terms of the fraction are to be divided, and it is reduced to... | |
 | Daniel Adams - 1833 - 268 σελίδες
...of ^ two numbers : — Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Frederick Emerson - 1833 - 198 σελίδες
...Divide the greater number by the smaller, then divide the divisor by the remainder; and thus continue dividing the last divisor by the last remainder, till nothing remains. The divisor used last of all, will be the greatest common divisor. 3. Find the greatest common divisor... | |
 | Frederick Emerson - 1832 - 344 σελίδες
...Divide the greater number by the smaller, then divide the divisor by the remainder; and thus continue dividing the last divisor by the last remainder, till nothing remains. The divisor used last of all, will be he greatest common divisor. 3. Find the greatest common divisor of... | |
 | Frederick Emerson - 1834 - 300 σελίδες
...ULE. Divide the greater number by the smaller, and this divisor by the remainder, and thus continue dividing the last divisor by the last remainder, till nothing remains. The divisor last used will be the number required. When the greatest common measure of more than two numbers... | |
 | Nathan Daboll - 1837 - 262 σελίδες
...a common measure, by dividing the greater term by the less, and this' divisor by the remainder, and so on, always dividing the last divisor by the last...2. Divide both of the terms of the fraction by the common measure, ^nd the quotients will make the fraction required. * To find the greatest common measure... | |
 | James Thomson (LL.D.) - 1837 - 296 σελίδες
...greater number by the less. (2.) If there be a remainder, divide the less by it ; and thus proceed, always dividing the last divisor by the last remainder, till nothing remains. The divisor Avhich leaves no remainder is the common measure required. If in the operation any divisor... | |
 | Daniel Adams - 1839 - 268 σελίδες
...of two numbers : — Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
| |
