 Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor' by the last remainder, till nothing remains, the last divisor is the common measure.* 2. Divide both of the...  Daboll's Schoolmaster's Assistant - Σελίδα 156των Nathan Daboll - 1828 - 247 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Nathan Daboll - 1839 - 220 σελίδες
...of two numbers RULE. Divide the greater number by the less, and this divisor by the remainder, and so on, always dividing the last divisor by the last remainder till nothing remain ; and the last divisor will be the common divisor. EXAMPLES. 1. What is the greatest common... | |
 | Bewick Bridge - 1839 - 280 σελίδες
...the greatest common measure of two numbers : " Divide the greater by the lesser, and the preceding divisor by the last remainder, till nothing remains ; the last divisor is the greatest common measure." To find the greatest common measure of three numbers, a, b c; let d be the... | |
 | Richard W. Green - 1840 - 300 σελίδες
...Divide the greater number by the less, and then divide the divisor by the remainder; and thus continue dividing the last divisor by the last remainder, till nothing remains. The last divisor will be the greatest common divisor. To find the common divisor of more than two numbers, find first... | |
 | Daniel Adams - 1840 - 278 σελίδες
...Oj two numbers : — Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Roswell Chamberlain Smith - 1841 - 324 σελίδες
...— GENERAL RULE. 16. Divide the greater number by the less, and that divisor by the remainder, and so on ; always dividing the last divisor by the last...remainder, till nothing remains ; the last divisor is the greatest common divisor required. 17. When the last divisor is 1, the given numbers are prime to each... | |
 | Roswell Chamberlain Smith - 1842 - 320 σελίδες
...— GENERAL RULE. 16. Divide the greater number by the less, and that divisor by the remainder, and so on ; always dividing the last divisor by the last...remainder, till nothing remains ; the last divisor is the greatest common divisor required, 17. When the last divisor is 1, the given numbers are prime to each... | |
 | Commissioners of National Education in Ireland - 1842 - 160 σελίδες
...once, divide the greater term by the less, and the divisor by the remainder ; and so on, dividing each divisor by the last remainder till nothing remains. The last divisor is the number by which, if the numerator and denominator of the fraction be divided, the lowest term will... | |
 | Lewis Joerres - 1842 - 190 σελίδες
...23. "Divide the greater number by the smaller and this divisor by the remainder, and thus continue dividing the last divisor by the last remainder till nothing remains; the divisor last used will be the number required. Example. — What is the greatestcommon measure of 918,... | |
 | Roswell Chamberlain Smith - 1843 - 320 σελίδες
...following,— GENERAL RULE. 16. Divide the greater number by the less, and that divisor by the remainder, and so on; always dividing the last divisor by the last...remainder, till nothing remains; the last divisor is the greatest common divisor required. 17. When the last divisor is 1, the given numbers are prime to each... | |
 | Nathan Daboll - 1843 - 260 σελίδες
...and so on. always dividing this last divisor by the last, remainder, till nothing remains ; the lust divisor is the- common measure.* 2. Divide both of the terms of the fraction by the com-- inon measure, and the quotients will make the fraction required. * To find the greatest common measure... | |
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