...length of the rectangle is 4 times its breadth. Compare their areas. PROPOSITION III. THEOREM. 363. The area of a rectangle is equal to the product of its base and altitude. i ZJ Let B be the rectangle, b the base, and a the altitude; and let U be a square whose side is equal...

...sides, and s their sum, A= V««-a)« If the triangle is equilateral and s = length of a side, 50. The Area of a Rectangle is equal to the product of its length and breadth, or A = bl where b = breadth and I = length. 51. The Area of a Parallelogram is...

...-which represent them when they are measured by the linear unit (III., 8). PROPOSITION IV.—THEOREM. 9. The area of a rectangle is equal to the product of...rectangle, k its base, and h its altitude numerically ex- i—i pressed in terms of the linear unit; — and let Q be the square whose side is the linear...

...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured ? Proposition I. A Theorem. 236. The area of a rectangle is equal to the product of its base and altitude. CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable. Proposition...

...those of Newton and Leibnitz, is that it is true. Let us next take the following proposition : — The area of a rectangle is equal to the product of its base and altitude. This is first established in the case where the base and altitude are commensurable. It need only be...

...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured? Proposition I. A Theorem. 236. The area of a rectangle is equal to the product of its base and altitude. . CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable. Proposition...

...its altitude 39 inches. Reduce to the same unit, and compare. AnS. 4^-. Proposition 3. Theorem. 360. The area of a rectangle is equal to the product of its base and altitude. Hyp. Let R be the rectangle, b the base, and a the altitude expressed in numbers of the same linear...

...that a line tangent to a circle is perpendicular to the radius drawn to the point of contact. 6. Prove the area of a rectangle is equal to the product of its base by its altitude. How would you prove the same for a parallelogram? 7. Problem: Given the hypotenuse...

...represent them when they are measured by the linear unit (III., 8). PROPOSITION IV.— THEOREM. 9. The area of a rectangle is equal to the product of its base and altitude. Let E be any rectangle, k its base, and h its altitude numerically expressed in terms of the linear unit...

...v., PROP. XIv.) Dividing both terms of the first couplet by 0 gives PROPOSITION XIII. 352. Theorem : The area of a rectangle is equal to the product of its base and altitude. Statement : Let R be any rectangle ; 6, its base ; and a, its altitude. The rectangle R is equal to...