 | Roswell Chamberlain Smith - 1842 - 320 σελίδες
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | Roswell Chamberlain Smith - 1843 - 320 σελίδες
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 σελίδες
...first or left hand period, and put its root for a quotient. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. 5. Double the quotient figure, for the first portion of the divisor ; then find what figure... | |
 | Charles Haynes Haswell - 1844 - 298 σελίδες
...left-hand period, and plnce Its root in the quotient; subtrnct the square number from the left-hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; find how many times the divisor is contained... | |
 | Horatio Nelson Robinson - 1845 - 310 σελίδες
...its root on the right of the given number; subtract said square from the left-hand period, and to /he remainder bring down the next period for a dividual....root for a divisor, and try how often this divisor (ivith the figure used in the trial thereto annexed] is contained in the dividual : set the number... | |
 | Almon Ticknor - 1846 - 276 σελίδες
...hand period, and place <he root to the right of the given number, and subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Square the root, and multiply it by three for a defective divisor. 4. Reserve mentally... | |
 | James Bates Thomson - 1846 - 362 σελίδες
...2 on the right of the given number for tke first figure in the root, we subtract its cube from the period, and to the remainder bring down the next period for a dividend. This shows that we have 7625 solid feet to be added to the cubical mound already found. 3.... | |
 | James Bates Thomson - 1846 - 354 σελίδες
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square... | |
 | James Bates Thomson - 1846 - 402 σελίδες
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square... | |
 | Joseph Ray - 1848 - 250 σελίδες
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Double the root already found, and place it on the left for a divisor. Find how many... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
