 | John EWART (Land Surveyor.) - 1847 - 108 σελίδες
...of the squares of the other sides ; and either of the sides containing the right angle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Then, to find the hypothenuse of a right-angled triangle from the other sides being... | |
 | Sir Henry Edward Landor Thuillier - 1851 - 826 σελίδες
...of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other; the square root of the difference of the squares of the hypothenuse and given side will be the required side. THEO. XIV. In all circles the chord of 60 degrees is always equal in... | |
 | Francis Walkingame - 1855 - 186 σελίδες
...top of the wall. Ans. 39-05 fed. fhc hypotfienuse and perpendicular given, to find tlie base. EULE. The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypotlienuse given, to find the perpendicular.... | |
 | Silas Lawrence Loomis - 1859 - 324 σελίδες
...difference of the squares of the Jiypothenuse and base. PROB. CUI. — To FIND THE BASE. RULE. — The square root of the difference of the squares of the hypothenuse and perpendicular. PROB. CIV. — To FIND THE AREA OF A TRIANGLE, THE BASE AND ALTITUDE BEING GIVEN. RULE.... | |
 | Francis Walkingame - 1865 - 222 σελίδες
...top of the wall? Ans. 39-05 feet. The hypothenuse and perpendicular given to find the base. RULE. — The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypothenuse given to find the perpendicular.... | |
 | Richard Nelson - 1867 - 304 σελίδες
...square root of the sum of the squares of the base and perpendicular will give the hypothenuse. And the square root of the difference ,of the squares of the hypothenuse and either of the two sides will give the third side. 22. What length of a ladder will reach across a 15-foot... | |
 | Francis Walkingame - 1868 - 154 σελίδες
...wall. Ans. 29-05 feet, and 975 rem. The Hypoihenuse and Perpendicular given to find the Base. RULE. — The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. (8) There is a tower of 103 feet in height, standing close... | |
 | Henry Bartlett Maglathlin - 1869 - 332 σελίδες
...the other two sides; and . 3. Hither of the two shorter sides of a right-angled triangle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Exercises. 1. If the base of a right-angled triangle is 60 feet, and the perpendicular... | |
 | David Munn - 1873 - 160 σελίδες
...-AC" 2 (2) = v/(AB +AC)(AB-AC) (3). Interpreting formula (2), we find the remaining side, by taking the square root of the difference of the squares of the hypothenuse and given side. Interpreting formula (3), we find the remaining side, by taking the square root of the product... | |
 | Henry Bartlett Maglathlin - 1873 - 362 σελίδες
...the other two sides; and 3. Either of the two shorter sides of a right-angled triangle is equal to the square root of the difference of the squares of the hypothenuse and the other side. Exercises. 1. If the base of a right-angled triangle is 60 feet, and the perpendicular... | |
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The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the... 
