 | Benjamin Greenleaf - 1851 - 332 σελίδες
...for the first figure of the root, and the square number under the period, subtracting it therefrom ; and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4 . Find... | |
 | Joseph Ray - 1852 - 408 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the kft period, and to the remainder bring down the next period for a dividend. 3rd. Dovlle the root already found, and place it on the left for a divitor. Find how many times the... | |
 | Joseph Ray - 1848 - 250 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
 | Ezra S. Winslow - 1853 - 264 σελίδες
...period, and place its root in the quotient ; subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Multiply the square of the quotient by 300, for a divisor; see how many times the divisor is contained... | |
 | James Gray - 1854 - 120 σελίδες
...that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide the dividend... | |
 | Benjamin Greenleaf - 1854 - 342 σελίδες
...for the first figure of the root, and the square number under the period, subtracting it therefrom ; and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor, 4. Find... | |
 | Roswell Chamberlain Smith - 1856 - 334 σελίδες
...on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,... | |
 | Benjamin Greenleaf - 1857 - 452 σελίδες
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,... | |
 | Joseph Ray - 1857 - 348 σελίδες
...and place its root on the right. as in division. Subtract the cube of the root from the left period, and' to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial, divisor. Find how many times this divisor... | |
 | Charles Guilford Burnham - 1857 - 328 σελίδες
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see how often the divisor is contained in the dividend,... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
