 | Benjamin Greenleaf - 1858 - 456 σελίδες
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Horatio Nelson Robinson - 1859 - 352 σελίδες
...write its root for the first figure in the root; subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. 70 70 Two Divisors — 1W Complete Divisor= 143 3 i J III. At the left of the dividend write twice... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the root, and-... | |
 | Daniel Adams - 1861 - 452 σελίδες
...period, and place its root in the quotient. III. Subtract the cube thus found from the period taken, and to the remainder bring down the next period for a dividend. IV. Calling the quotient, or root figure now obtained, so many tens, multiply its square by 3, and... | |
 | Benjamin Greenleaf - 1861 - 338 σελίδες
...left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each, by placing... | |
 | John Flint (inspector of schools.) - 1862 - 152 σελίδες
...and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the dividend... | |
 | Benjamin Greenleaf - 1863 - 338 σελίδες
...left-hand period, and place its root on the right ; subtract the square of this root from the first period, and to the remainder bring down the next period for a dividend. 4356 36 126 756 756 ELEMENTARY ALGEBRA. Divide this quantity, omitting the last figure, by double the... | |
 | Horatio Nelson Robinson - 1863 - 432 σελίδες
...place its foot for the ßrst figure of the required root ; subtract this cube from the first period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of the root already found, and annex... | |
 | Benjamin Greenleaf - 1864 - 420 σελίδες
...left-hand period, and place its root on the right ; subtract the square of this root from the first period, and to the remainder bring down the next period for a dividend. Divide this quantity, omitting the last figure, by double the part of the root already found, and annex... | |
 | George Augustus Walton - 1864 - 364 σελίδες
...period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
