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" Rule. — Divide the numerator by the denominator, the quotient will be the whole number... "
An Elementary Treatise on Arithmetic, in Theory and Practice: Adapted to the ... - Σελίδα 129
των James Ryan - 1827 - 276 σελίδες
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Examination essentials

John Robertson (LL.D., of Upton Park sch.) - 1861 - 140 σελίδες
...and retain the same denominator. Rule 3. To reduce an improper fraction to a whole or mixed number. Divide the numerator by the denominator, the quotient will be the whole number, and the remainder, if any, the numerator of the fractional part of the mixed number required. Obs....

First book of arithmetic for the use of schools. [With] Key. High-school ed ...

Ireland commissioners of nat. educ - 1865 - 184 σελίδες
...2345Jif, lllAVr to improper fractions. Case III. — To reduce an improper fraction to a mired number. RULE.— Divide the numerator by the denominator; the quotient will be the whole number ; and, if there be any remainder, place it as the numerator of the fraction. EXAHILE 1. — Reduce...

Arithmetic for the use of Schools. Designed to assist Candidates preparing ...

W. M. LUPTON - 1867 - 210 σελίδες
...189^. (24) S86&. (25) 8691|2. To reduce an improper fraction to a whole or mixed number. BULB. — Divide the numerator by the denominator, the quotient will be the whole number ; if there should be a remainder that will form the numerator of the fractional part of the mixed number,...

Practical Arithmetic, by Induction and Analysis

Joseph Ray - 1857 - 358 σελίδες
...number. OPERATION, 4)9 Ans. $2|. OPERATION. 5)17 Ant. 3f Ant. 2T*0. Ant. 8|. Rule for Case II. — Divide the numerator by the denominator : the quotient will be the whole or mixed number. Ant. 13J. 1. In s;j3 of a dollar, how many dollars? 8. In 7?5 of a yard, how many...

The Rudiments of Arithmetic: Embracing Mental and Written Exercises for ...

Joseph Ray - 1866 - 212 σελίδες
...° / ^ in 291, which is 36| times. 36|, Ans. CONCLUSION. — Therefore, ^f1- equal 36|. Hence, the Rule. — Divide the numerator by the denominator; the quotient will be the whole or mixed number. MENTAL EXEECISES. Eeduce the following to whole or mixed numbers : 2. J,i. 6. Y- 10....

The Principles of Arithmetic ...

Joseph Ray - 1856 - 400 σελίδες
...34 * • 783 10. 923 11CASE II. TO REDUCE AN IMPROPER FRACTION TO A WHOLE OR MIXED NUMBER. ART. 120. RULE. — Divide the numerator by the denominator; the quotient will be the whole or mixed number. 0 NOTE.— If there be a fraction in the answer, reduce it to its lowest terms. To...

Moffatt's pupil teachers' course (ed. by T. Page). Candidates, 2nd (-4th) year

Moffatt and Paige - 1879 - 428 σελίδες
...improper fraction to a whole or mixed number. This operation is evidently the converse of the preceding. Rule. Divide the numerator by the denominator. The quotient will be the whole number, and the remainder will be the numerator of the fractional part of the mixed number. The denominator...

Ray's Elementary Arithmetic: Embracing Mental and Written Exercises, for ...

Joseph Ray - 1879 - 200 σελίδες
...times in 291. 291 g \ 291 -H 8 = 36|. 36| , Ans. CONCLUSION. — Therefore, *-|i equal 36|. Hence, the Rule. — Divide the numerator by the denominator; the quotient will be the whole or mixed number. 4. jfr. 8. MO 12. 231 MENTAL EXERCISES. Eeduce the following improper fractions to...

A treatise on arithmetic. [With] Key, Τόμος 1

James Thomson - 1880 - 408 σελίδες
...rSS T29' T29' 729' T29I T29' T55 RULE V. To reduce an improper fraction to a whole or mixed number : Divide the numerator by the denominator ; the quotient...denominator for the fractional part of the required result. The reason of this rule and that of the next are evident from the nature of fractions. Ex«m. 7. Reduce...

Ray's New Higher Arithmetic: A Revised Edition of the Higher Arithmetic

Joseph Ray - 1880 - 420 σελίδες
...be as many dollars in 13 fifths as 5 fifths are contained times in 13 fifths ; that is, 2g dollars. Rule. — Divide the numerator by the denominator ; the quotient will be the whole or mixed number. REMARK. — If there be a fraction in the answer, reduce it to its lowest terms. 1....




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