 | Catharine Esther Beecher - 1833 - 296 σελίδες
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, and to the remainder bring down the next period, for a dividend. 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor.... | |
 | William Templeton (engineer.) - 1833 - 224 σελίδες
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... | |
 | Frederick Emerson - 1834 - 300 σελίδες
...greatest square in the left hand period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... | |
 | Charles Potts - 1835 - 202 σελίδες
...cube in the left hand period, and set its root on the right of the given number ; subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root, and multiply the square by 3 for a defective divisor. 4. Reserve, mentally,... | |
 | Benjamin Snowden - 1835 - 108 σελίδες
...and put its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this... | |
 | Stephen Pike - 1835 - 210 σελίδες
...root. 2. lind the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that... | |
 | James L. Connolly (mathematician.) - 1835 - 264 σελίδες
...not too great, of the first period, for the first figure of your root, subtract its cube from said period, and to the remainder bring down the next period for a resolvend. Take three times the square of the root for a defective divisor, and seek how often it is... | |
 | George Willson - 1836 - 202 σελίδες
...for the first figure of the root, and the square itself under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and annex a cipher to tho product, for a divisior. Seek how many times... | |
 | Silas Totten - 1836 - 332 σελίδες
...at the right, after the manner of a quotient in division. Subtract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300, for a divisor. Seek how often the divisor is... | |
 | 1836 - 488 σελίδες
...subtract from the highest period the greatest square contained in it, place the root in the quotient, and to the remainder bring down the next period for a dividend. 2. Double the root already found, (understanding a cypher at the right,) for a divisor, and divide... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend... 
