 | Charles Guilford Burnham - 1857 - 342 σελίδες
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the... | |
 | Benjamin Greenleaf - 1858 - 332 σελίδες
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and... | |
 | Benjamin Greenleaf - 1858 - 456 σελίδες
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...left-hand period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor... | |
 | Horatio Nelson Robinson - 1859 - 362 σελίδες
...left hand period, and write its root for the first figure in the root ; subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Fig. III. 70 i Two Divisors = 140 1 70. 3 Complete Divisor = 143 III. At the left of the dividend write... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...left hand period, and write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the root, and-... | |
 | Dana Pond Colburn - 1860 - 388 σελίδες
...hand period, and place its root as the first figure of the required root. Third. Subtract this cube from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourih. Find three times tlie square of the part of the root already... | |
 | Benjamin Greenleaf - 1861 - 338 σελίδες
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each, by placing... | |
 | Daniel Adams - 1861 - 452 σελίδες
...period, and write its root as a quotient in division. Subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | John Flint (inspector of schools.) - 1862 - 152 σελίδες
...in the left hand period, and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the dividend... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend... 
