 | Benjamin Williamson - 1877 - 372 σελίδες
...sphere; and we get 471- .R2 for the entire surface of the sphere. Hence, the surface of a sphere is equal to four times the area of one of its great circles. Again, it is easy to find the surface generated by any number of sides of the polygon. Thus, for example,... | |
 | William Henry Harrison Phillips - 1878 - 236 σελίδες
...4»R2. Coit. 2. The area of a great circle = «R2 (IV., 12, Cor. 3) : hence the surface of a sphere is equal to four times the area of one of its great circles. BOOK VIII.] MEASUREMENT OF SOLIDS. COR. 3. The surfaces of two spheres are to each other as the squares... | |
 | Samuel Earnshaw - 1881 - 602 σελίδες
...discovered them. In like manner, none before Archimedes had discovered that the surface of a sphere is equal to four times the area of one of its great circles (prop. 35) ; the volume of a sphere to two thirds of the circumscribed cylinder having the same altitude,... | |
 | Charles Taylor - 1881 - 486 σελίδες
...discovered them. In like manner, none before Archimedes had discovered that the surface of a sphere is equal to four times the area of one of its great circles (prop. 35) ; the volume of a sphere to two thirds of the circumscribed cylinder having the same altitude,... | |
 | John Ogilvie - 1883 - 834 σελίδες
...circumscribing cylinder. Spheres are to one another as the cubes of their diameters. The surface of a sphere is equal to four times the area of one of its great circles, and the solidity is found by multiplying the cube of the diameter by •5236 or 3 of 7854; or by multiplying... | |
 | John Ogilvie - 1883 - 830 σελίδες
...circumscribing cylinder. Spheres are to one another as the cubes of their diameters. The surface of a sphere Is equal to four times the area of one of its great circles, and the solidity is found by multiplying the cube of the diameter by •5230 or 3 of 7854; or by multiplying... | |
 | Benjamin Williamson - 1884 - 424 σελίδες
...sphere ; and we get 471- .ft2 for the entire surface of the sphere. Hence, the surface of a sphere is equal to four times the area of one of its great circles. Again, it is easy to find the surface generated by any number of sides of the polygon. Thus, for example,... | |
 | Daniel Kinnear Clark - 1892 - 682 σελίδες
...cylinder. The surface of a sphere is equal to the productif the square of the diameter by 3-1416. It is equal to four times the area of one of its great circles. 'I It is equal to the convex surface of its circumscribing cylinder. • .'.-••..' • - .' •... | |
 | Ainsworth Rand Spofford, Charles Annandale - 1901 - 578 σελίδες
...circumscribing cylinder. Spheres are to one another as the cubes of their diameters. The surface of a sphere is equal to four times the area of one of its great circles, and the solidity is found by multiplying the cube of the diameter by •523ti or g of '7854; or by... | |
 | Alexander Russell Bond - 1904 - 572 σελίδες
...perpendicular height. SPHERE. — Area equals square of diameter multiplied by 3.141t» or 3J; ie, it is equal to four times the area of one of its great circles, or to the convex surface of its circumscribing cylinder. Surfaces of spheres vary as the squares of... | |
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The surface of a sphere Is equal to four times the area of one... 
