 | John Bonnycastle - 1825 - 336 σελίδες
...root of the first term in the quotient. 2. Subtract the square of the root, thus found from the first term, and bring down the two next terms to the remainder for a dividend. p 3. Divide the dividend, thus found, by double that part of the root already determined, and set the... | |
 | John Bonnycastle - 1829 - 372 σελίδες
...root of the first term ID the quotient. 2. Subtract the square of the root thus found, from the first term, and bring down the two next terms to the remainder for a dividend. p 3. Divide the dividend, thus found, by double that part 'of the root already determined, and set... | |
 | John Bonnycastle - 1836 - 296 σελίδες
...term in the quotient. 2. Subtract the square of the root, thus found, from the first term, and brina; down the two next terms to the remainder, for a dividend. 3. Divide this dividend by double that part of the root already determined, and set the result both in the quotient... | |
 | Alexander Ingram - 1844 - 262 σελίδες
...root of the first term for the first term of the root; subtract its square from the given quantity, and bring down the two next terms to the remainder for a resolvend. Double the root for a divisor, by which divide the first term of the resolvend to get another... | |
 | John Bonnycastle - 1851 - 288 σελίδες
...root of the first term in the quotient. 2. Subtract the square of the root thus found, from the first term, and bring down, the two next terms to the remainder for a dividend. 4. Multiply the divisor, so increased, by the term of the root last placed in the quotient, and subtract... | |
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... and set the root of the first term in the quotient. 2. Subtract the square of the root, thus found from the first term, and bring down the two next terms to the remainder for a dividend. 3. Divide the dividend... 
