 | Joseph Ray - 1852 - 422 σελίδες
...the first and second terms by the third, plus the square of the third. Multiply these by the third term of the root and subtract the product from the last remainder. 4th. Continue this process titt all the terms of the root are found. vy NOTE. — The remainder in... | |
 | Elias Loomis - 1868 - 386 σελίδες
...to it three times the product of the two terms of the root and the square of the second term. 4cth. Multiply the divisor thus increased by the last term...and subtract the product from the last remainder. 6th. Take three times the square of the part of the root already found for a new trial divisor, and... | |
 | William Frothingham Bradbury - 1868 - 264 σελίδες
...found, and annex the result both to the root and to the divisor. Multiply the corrected divisor by this last term of the root, and subtract the product from the last remainder. Proceed as before with the remainder, if there is any. 2. Find the square root of 4 a;2 — 4 xy3 + y4. Ans.... | |
 | John Fair Stoddard - 1868 - 428 σελίδες
...places to the right, to the last term of the 2d column for the TRUE orviSOE. Multiply this divisor by the last term of the root, and subtract the product from the dividend, and to the remainder annex the next period, for the SECOND DIVIDEND. 6. Proceed in like manner... | |
 | John Fair Stoddard - 1888 - 480 σελίδες
...ices to the right, to the last term of the 2d column for the TBUE DIVISOK. Multiply this divisor lij the last term of the root, and subtract the product from the dividend, and to the remainder annex the next period, for the SECOND DIVIDEND. 6. Proceed in like manner... | |
 | Elias Loomis - 1873 - 396 σελίδες
...times the product of the two terms of the root and the square of the second term. 4th. Multiply Hie divisor thus increased by the last term of the root, and subtract the product from Hie last remainder. 5Hi. Take three times the square of the part of the root already found for a new... | |
 | James Cahill (of Dublin.) - 1875 - 230 σελίδες
...of the two terms now in the root's place, and the square of the last term. (5) Multiply the divisor by the last term of the root, and subtract the product from the dividend. Proceed as in (3) and (4) to find a new divisor and the remaining term or terms of the root.... | |
 | Edwin Pliny Seaver, George Augustus Walton - 1878 - 414 σελίδες
...the root (tens) multiplied by the last term, also the square of the last term. 6. Multiply this sum by the last term of the root, and subtract the product from the dividend. 7. If there are more terms of the root to be found, unite with the remainder the next three... | |
 | Benjamin Greenleaf - 1879 - 376 σελίδες
...by the second, and the square of the second, for a complete divisor. Multiply the complete divisor by the last term of the root,, and subtract the product from the remainder. If there are other terms remaining, continue the operation in the same manner as before.... | |
 | Benjamin Greenleaf - 1879 - 350 σελίδες
...the second, and the square of the second, for a complete divisor. Multiply the complete divisor Ъу the last term of the root, and subtract the product from the remainder. If there tire oilier terms remaining, continue the operation in the same manner as before.... | |
| |
Multiply the divisor thus increased by the last term of the root, and subtract the product from the last remainder. 
